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xz_007 [3.2K]
3 years ago
6

A drug is supplied as a 40 mg/ml solution in a 50 ml vial. you need to make 10 ml of a 10 mg/ml solution. how much concentrate w

ill be needed? ml how much diluent will be needed? ml
Chemistry
1 answer:
Ymorist [56]3 years ago
8 0

Answer: -

2.5 mL

Explanation: -

Volume of final solution = 10 mL

Strength of final solution = 10 mg / mL

Amount of drug required = Volume of final solution x strength of final solution

= 10 mL x 10 mg/ mL

= 100 mg.

Strength of supplied drug = 40mg/ mL

Volume of supplied drug required = \frac{100 mg}{40 mg/ mL}

= 2.5 mL

Thus to make 10 ml of a 10 mg/ml solution. 2.5 mL will be needed.

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And you can use Aufbau's rule to predict the atomic number of the next elements.

Radon, Rn is the element number 86.

Following Aufbau's rules, the electron configuration of Rn is: [Xe] 6s2 4f14 5d10 6p6. This means that you are suming 2 + 14 + 10 + 6 = 32 electrons with respect to the element Xe.

You can verity that the atomic number of Xe is 54, so when you add 32 you get 54 + 32 = 86, which is the atomic number of Rn.

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So the next element of the group will have ; 2 + 18 + 14 + 10 + 6 = 50 electrons, which means that the atomic number of this, not yet discovered element, has atomic number 118 + 50 = 168.

By the way the element with atomic number 118 was already discovdered at its symbol is Og. You can search that information in internet.

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