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1 year ago

HNO3(aq)+H2S(s)> Ss)+ NO(g)+H2O(l)

Chemistry

1 answer:

sveta [45]1 year ago

4 0

Answer: Nitric acid + Hydrogen disulfide

Explanation: To balance HNO3 + H2S = NO + S + H2O you'll need to be sure to count all of atoms on each side of the chemical equation.

Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Nitric acid + Hydrogen disulfide .

Important tips for balancing chemical equations:

Only change the numbers in front of compounds (the coefficients).

Never change the numbers after atoms (the subscripts).

The number of each atom on both sides of the equation must be the same for the equation to be balanced.

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How do you determine the volume of a regular object if you don't know the density?

Ann [662]

Answer:

mol times or devided by molar volume

4 0

2 years ago

If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?

Pie

Answer:

$m = \frac{E}{c^2}$

$c = \sqrt{\frac{E}{m} }$

$E = 12.8 J$

Explanation:

Part 1: Solving for m

We are given that:

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

$m = \frac{E}{c^2}$

Part 2: Solving for c

We are given that:

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

$c^2 = \frac{E}{m}\\ \\ c=\sqrt{\frac{E}{m}}$

Part 3: Solving for E

We are given that:

m = 80 and c = 0.4

To get the value of E, we will simply substitute in the given equation:

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0

3 years ago

Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma

marishachu [46]

Answer:

why did you post a link to brainly when we are on brainly already??????

Explanation:

8 0

2 years ago

Calculate the concentration of A bottle of wine contains 12.9% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm e

Delicious77 [7]

Answer:

The mass percentage of the solution is 10.46%.

The molality of the solution is 2.5403 mol/kg.

Explanation:

A bottle of wine contains 12.9% ethanol by volume.

This means that in 100 mL of solution 12.9 L of alcohol is present.

Volume of alcohol = v = 12.9 L

Mass of the ethanol = m

Density of the ethanol ,d= $0.789 g/cm^3=0.789 g/mL$

$1 cm^3=1 mL$

$m=d\times v=0.798 g/ml\times 12.9 mL = 10.1781 g$

Mass of water = M

Volume of water ,V= 100 mL - 12.9 mL = 87.1 mL

Density of water = D=1.00 g/mL

$M=D\times V=1.00 g/ml\times 87.1 mL =87.1 g$

Mass percent

$(w/w)\%=\frac{m}{m+M}\times 100$

$\frac{10.1781 g}{10.1781 g+87.1 g}\times 100=10.46\%$

Molality :

$m=\frac{m}{\text{molar mass of ethanol}\times M(kg)}$

M = 87.1 g = 0.0871 kg (1 kg =1000 g)

$=\frac{10.1781 g}{46 g/mol\times 0.0871 kg}$

$m=2.5403 mol/kg$

4 0

3 years ago

Consider the equation for the formation of water.

Juli2301 [7.4K]

The theoretical yield is 160 g H₂O.

Moles of H₂ = 18 g H₂ × (1 mol H₂/2.016 g H₂) = 8.93 mol H₂

Moles of H₂O = 8.93 mol H₂O × (2 mol H₂O/2 mol H₂) = 8.93 mol H₂O

Theoretical yield of H₂O = 8.93 mol H₂O × (18.02 g H₂O/1 mol H₂) = 160 g H₂O

6 0

3 years ago