Answer: 37.6 atm
Explanation:
Given that,
Initial volume of gas (V1) = 19L
Initial pressure of gas (P1) = 9.5 atm
Final volume of gas (V2) = 4.8L
Final pressure of gas (P2) = ?
Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law
P1V1 = P2V2
9.5 atm x 19L = P2 x 4.8L
180.5 atm•L = 4.8L•P2
Divide both sides by 4.8L
180.5 atm•L/4.8L = 4.8L•P2/4.8L
37.6 atm = P2
Thus, the final pressure is 37.6 atmospheres.
Answer:
Explanation has been given below.
Explanation:
- Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
- Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
- First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
- Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
- Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
- Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.
Answer: varriable
Explanation:meaning one element, feature or factor able to change
5. 1 hydrogen, 1 Nitrogen, 3 oxygen
