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3 years ago

What happens in a reduction?

Chemistry

2 answers:

MatroZZZ [7]3 years ago

6 0

Answer:

A. An element gains one or more electrons

Explanation:

Reduction is a chemical reaction that involves the gaining of electrons by one of the atoms involved in the reaction between two chemicals. The term refers to the element that

sattari [20]3 years ago

6 0

Answer:

The answer is C

Explanation:

Just did this on apex rn lol

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How many electrons are in the highest occupied energy level of these atoms?

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2 years ago

The relationship between the endoplasmic reticulum and the Golgi complex is most similar to which of these examples? A a factory

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2 years ago

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2 years ago

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How many moles are in a solution that has a molarity of 3.0M and a volume of 1500 ml.

Bad White [126]

Answer:

1.25 Moles

Explanation:

1.25 moles of solute

Explanation:

Molarity is defined as the number of moles of solute per liter of solution.

Molarity = moles of solute / liter of solution

We are given the molarity and volume, both of which have the correct units. All we have to do is rearrange the equation to find the number of moles. You can do this by multiplying both sides of the equation by the volume to cancel it out on the right hand side. Afterwards, you should end up having the volume multiplied by the molarity equaling the number of moles of solute like so:

Moles of solute = Molarity * Volume

2.5M HCl * 0.5 L = 1.25 moles of HCl

I hope this made sense.

3 0

2 years ago

g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o

Liono4ka [1.6K]

Answer:

pOH = 0.36

Explanation:

Both potassium hydroxide and lithium hydroxide solutions are strong bases, so you assume 100% dissociation.

1. Potassium hydroxide solution, KOH

Volume, V = 304 mL = 0.304 liter

Molarity, M = 0.36 M

number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol

1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

2. LIthium hydroxide, LiOH

Volume, V = 341 mL = 0.341 liter

Molarity, M = 0.51 M

number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol

1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

3. Resulting solution

Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

4. pOH

$pOH=-\log [OH^-]=-\log (0.439)=0.36$ ← answer

5 0

2 years ago