Answer:
Because work can be defined as force time distance, we can also use the following equation
Solution
P=power (w or ft-lbf/s)
F=force (N or lbf)
D=distance (m or ft)
T=time (sec)
One horsepower is equivalent to 550 ft-lbf/s and 745.7 watts.
The trade winds are located about 30 degrees north and south of the equator.
Answer:
magnitude of v = 2.5 m/s, and in the same direction as the initial velocity of the 5 kg ball.
Explanation:
We use conservation of linear momentum in an elastic collision to solve for the unknown velocity v:
Pi = Pf
5 kg * 5 m/s + 10 kg * 0 m/s = 5 kg * 0 m/s + 10 kg * v
25 kg m/s = 10 kg * v
v = 25/10 m/s
v = 2.5 m/s
and in the same direction as the initial velocity of the 5 kg ball.
Answer:
1.176m
Explanation:
Local ambient pressure(P1) = 100 kPa
Absolute pressure(P2)=260kPa
Net pressure=absolute pressure-local ambient absolute pressure
Net pressure=P1(absolute pressure)-P2(local ambient absolute pressure)
Net pressure=260-100=160kPa
Pressure= ρgh
160kPa=13600*10*h
h=
h=1.176m
