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Triss [41]
1 year ago
13

During the latter part of your European vacation, you are hanging out at the beach at the gold coast of Spain. As you are laying

in your chaise lounge soaking up the warm Mediterranean sun, a large glob of seagull poop hits you in the face. Since you got an “A” in ICPE you are able to estimate the impact velocity at 98.5 m/s. Neglecting air resistance, calculate how high up the seagull was flying when it pooped.
Physics
1 answer:
adelina 88 [10]1 year ago
6 0

The maximum height attained is 460 m.

<h3>What is the maximum height?</h3>

We know that the final velocity of a body is 0 m/s at the maximum height which is the greatest height that is attained by the body. We now use the formula;

v^2 = u^2 -2gh

Given that v = 0 m/s

u^2 = 2gh

h = u^2/2g

v = final velocity

u = initial velocity

h = maximin height

g = acceleration due to gravity

h = (95)^2/2 * 9.8

h = 460 m

Learn more about maximum height:brainly.com/question/6261898

#SPJ1

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zimovet [89]

Answer:

a) v = 6.25\times 10^{5} m/s

b) v = 1.73\times 10^{4} m/s

Explanation:

Given data:

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distance of point b from point A is 0.55 m

we know that acceleration of particle is given as

a) for electron

a =\frac{q E}{m}

a = \frac{1.6\times 10^{-19} \times 1.47}{9.1\times 10^{-31}}

a = 2.58\times 10^{11} m/s^2

from equation of motion we have

v^2 = u^2 + 2aS

      = 20.7025 \times 10^{10} + 2\times 2.58\times 10^{11} \times 0.355

v = 6.25\times 10^{5} m/s

b) for proton

a = \frac{1.6\times 10^{-19} \times -1.47}{1.6\times 10^{-27}}

a = -1.41\times 10^{8} m/s^2

from equation of motion we have

v^2 = u^2 + 2aS

       = 3.8025 \times 10^{8} - 2\times 1.41\times 10^{8} \times 0.355

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3 0
2 years ago
2. A 50 kg diver is standing on the edge of a 15 m high cliff. What is his potential energy?
Lera25 [3.4K]

Answer:

3675 J

Explanation:

Gravitational Potential Energy = \frac{1}{2} × mass × g × height

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Mass = 50 kg

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Height = 15 m

Gravitational Potential Energy = \frac{1}{2} × 50 ×9.8 × 15

= 3675 J

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B, larceny because that's theft of personal property.

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