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Which times and distances are represented by the function? select three options. the starting distance, at 0 hours, is 300 miles

Naya [18.7K]

The times and distances are represented by the function are

at 2 hours, the traveler is 725 miles from home.
at 3 hours, the distance is constant, at 875 miles
the total distance from home after 6 hours is 1,062.5 miles.

<h3>What is distance?</h3>

The distance is the length of path travelled by a body when moving with some speed and taking time t.

Given function is

D (t) = 300t +125 for 0≤t<2.5

D (t) = 875 for 2.5 ≤t≤3.5

D(t)= 75t +612.5 for 3.5<t≤6

According to the given function, for 2 hours, the traveler will travel from home,

D (2) = 300x2 +125 = 725 miles.

For time between 2.5 to 3.5 hr, the distance is constant i.e. 875 miles.

For total time 6hr, the distance travelled will be

D(6) = 75 x 6 +612.5 = 1062.5 miles.

Thus, the correct options are picked up.

Learn more about distance.

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4 0

3 years ago

If a rock climber accidentally drops a 77.5-g piton from a height of 215 meters, what would its speed be just before striking th

Viktor [21]

Let us list out what we know from the question.

Initial Velocity $V_{i} = 0$ since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity $a = 9.8 m/s^{2}$

Final Velocity $V_{f} = ?$

Using the equation, $V^{2} _{f} = V^{2} _{i} + 2aD$ and plugging in the known values, we get

$V^{2} _{f} = 0^{2} + 2(9.8)(215)$

Simplifying by taking square-root on both sides gives us $V_{f} = 64.915 m/s$

Thus, the speed of the piton just before striking the ground is 65 m/s.

4 0

3 years ago

What feature of the ocean allows it to alter weather problems its water releases hydrogen that creates cold fronts its rising ti

katrin2010 [14]

<span>The size of the ocean, along with the large heat capacity of water,
allows the ocean to store large amounts of heat energy.</span>

6 0

4 years ago

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Jupiter is 5.2 times farther from the sun than Earth is. Find Jupiter’s orbital period in Earth years

anzhelika [568]

You can solve this using Kepler's 3rd law. T is proportional to r^1.5. T(J) = T(E)*5.2^1.5 = 11.86 years.
<span>You can also solve it the hard way: Find M (sun's mass) and r(Jupiter's orbital radius) in m. Then use Kepler's equation T = 2pi*r^1.5/sqrt(GM).</span>

8 0

4 years ago

What provides the centripetal force needed to keep Earth in orbit?

kkurt [141]

The centripetal force needed to keep earth in orbit is gravity.

3 0

3 years ago

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