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3 years ago

9

Place gamma rays, infrared, microwaves, radio waves, ultraviolet, visible light, and x-rays in order from largest wavelength to

smallest wavelength.

1 answer:

Brums [2.3K]3 years ago

7 0

Answer:

Going by EM SPECTRUM WE HAVE

radio waves, microwaves, infrared, VISIBLE LIGHT, ultraviolet, X-rays, GAMMA RAYS

Explanation:

BECAUSE

V= WAVELENGTH/ FREQUENCY

AS FREQUENCY INCREASES WAVELENGTH DECREASE AN VICE VERSA

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A 15.5 kg block is pulled by two forces. The first is 11.8N at a 53.7 angle and the second is 22.9 N at a -15.8 angle. What is t

anygoal [31]

Answer:

α = 6.43° (Angle respect to the horizontal axis-x)

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces must be equal to the product of mass by acceleration.

Since we have two forces and we know their magnitudes and their directions, we can sum these into their X & y components, in this way we can find the resulting force and apply it in Newton's second law.

F1x = 11.8*cos(53.7) = 6.98 [N]

F1y = 11.8*sin(53.7) = 9.5 [N]

Now with the second force:

F2x = 22.9*cos (15.8) = 22.03 [N]

F2y = - 22.9*sin (15.8) = - 6.23 [N]

Now we sum the forces in the x and y axes:

Fx = F1x + F2x = 6.98 + 22.03 = 29.01 [N]

Fy = F1y + F2y = 9.5 - 6.23 = 3.27 [N]

Now using the Pythagorean theorem we can find the resulting force.

F = √(Fx² + Fy²)

F = √ (29.01)² + (3.27)²

F = 29.19 [N]

Using Newton's second law, we have:

F = m*a

where:

F = force = 29.19 [N]

m = mass = 15.5 [kg]

a = acceleration [m/s²]

a = 29.19/15.5

a = 1.88 [m/s²]

The direction of the acceleration is the same direction of the force, therefore we need to find the angle.

tan(α) = Fy/Fx

tan(α) = 3.27/29.01

α = tan⁻¹(0.1127)

α = 6.43° (Angle respect to the horizontal axis-x)

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3 years ago

1.25 is closer to 1.04 or not ?<br> plz heelp plz

Romashka-Z-Leto [24]

Answer:

No, it is closer to 1.30

Explanation:

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3 years ago

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Setler79 [48]

What you’re doing is so easy pay attention more I think

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3 years ago

8. If the mass of a balloon is 300 kg and the lift force provided by the atmosphere is 3300 N, what

zmey [24]

Answer:

Toward the north, 300 N

Explanation:

Consider the upward direction as positive and downward direction as negative.

Given:

Mass of the balloon is, $m=300\ kg$

Lift force on the balloon in the upward direction is, $F_L=3300\ N$

Take acceleration due to gravity as 10 N/kg.

Now, weight of the balloon acting downward is given as the product of its mass and acceleration due to gravity. Therefore,

Weight is, $W=mg=(300\ kg)(10\ N/kg)=-3000\ N$

Now, net force is given as the vector sum of both the forces.

$F_{net}=F_L+W\\F_{net}=3300-3000=300\ N(\textrm{Upward direction})$

The upward direction is the direction of North. So, the net force acting on the balloon is 300 N towards North.

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3 years ago

The amount of charge flowing through a particular point in a conductor is represented by the equation Q = at^3 + bt + c, where a

stira [4]

Explanation:

Below is an attachment containing the solution.

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4 years ago