X rays because to see your bones
Answer:
gravitational force
electrostatic force
Explanation:
The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.
The Mutual force of gravitational pull that they exert on each other can be given as:

where:
gravitational constant 
are the masses of individual balloons
the radial distance between the center of masses of the balloons.
But when there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.
Given as:

where:

are the charges on the individual balloons
R = radial distance between the charges.
Answer:
so angular velocity is 7.13128 sec−1
Explanation:
velocity v = 2.2 m/s
displacement s = 220 mm = 0.220 m
distance d = 510 mm = 0.510 m
to find out
angular velocity
solution
we know that
angular velocity will be velocity ( v) / (displacement² + distance²) .....1
now put all these value in equation 1 and we get angular velocity i.e.
angular velocity = velocity ( v) / (displacement² + distance²)
angular velocity = 2.2 / (0.22² + 0.51²)
angular velocity = 2.2 / 0.3085
angular velocity = 7.13128
so angular velocity is 7.13128 sec−1
Answer:
Yes Newton's laws apply to small objects
EX: Newton s first law
when body at rest always want to be at rest
or body at motion always want to be at motion
unles an external force acts upon it
for example a eraser on the table will be at rest
if so e apply some force then it comes motion
so, Newton s law apply to small object s
Answer:16.096
Explanation:
Given
mass of dog
mass of boat
distance moved by dog relative to ground=
distance moved by boat relative to ground=
Distance moved by dog relative to boat=7.8m
There no net force on the system therefore centre of mass of system remains at its position
0=
0=

i.e. boat will move opposite to the direction of dog
Now

substituting
value



now the dog is 22.5-6.403=16.096m from shore