Answer:
[HI] = 0.7126 M
Explanation:
Step 1: Data given
Kc = 54.3
Temperature = 703 K
Initial concentration of H2 and I2 = 0.453 M
Step 2: the balanced equation
H2 + I2 ⇆ 2HI
Step 3: The initial concentration
[H2] = 0.453 M
[I2] = 0.453 M
[HI] = 0 M
Step 4: The concentration at equilibrium
[H2] = 0.453 - X
[I2] = 0.453 - X
[HI] = 2X
Step 5: Calculate Kc
Kc = [Hi]² / [H2][I2]
54.3 = 4x² / (0.453 - X(0.453-X)
X = 0.3563
[H2] = 0.453 - 0.3563 = 0.0967 M
[I2] = 0.453 - 0.3563 = 0.0967 M
[HI] = 2X = 2*0.3563 = 0.7126 M
So where the "following" at?
Answer:
7.208 g
Explanation:
0.4mol x 
= 7.208 g
You are using molar mass of H20 to find the mass. Moles of 0.4 and 1 mol cancel out leaving you with just grams. You get the values in the numerator from the periodic table and the 2(1.01) is because you have 2 of the H in H20
Answer: The earth's atmosphere gets thinner with the increase in altitude. The earth's atmospheric layers are Troposphere, Stratosphere, Mesosphere, Ionosphere .
Explanation:
Good luck!