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1 year ago

Which isotope in each pair is more stable? Why?(d) ¹⁴₇N or ¹⁸₇N

Chemistry

1 answer:

quester [9]1 year ago

6 0

<u>¹⁴₇N</u><u> </u>is the more stable isotope

<h3>Briefly explained</h3>

We have ¹⁴₇N which has a neutron to proton ratio of one, and we look at ¹⁸₇N which has a neutron to proton ratio of 1.57 Again, you look at table 24 to and you see the atomic number of seven and there is really no stable isotope. It has any more than 10 neutrons.

When we have eight, protons will go down seven protons. There's really nothing stable that has more than maybe eight neutrons. So the fact that we have 11 neutrons with ¹⁸₇N suggests that this is very unstable and

¹⁴₇N is the stable isotope of the pair.

<h3>Stable and Unstable Nuclei</h3>

An atom is electrically neutral. It contains an equal number of positively charged protons and negatively charged electrons and their charges balance. The nucleus however contains only positively charged protons which are closely packed together in a very small volume (remember neutrons have no charge).

From the laws of physics (Coulomb’s Law) one would expect that the protons being of the same charge and so close together would exert strong repulsive forces on each other. The combined gravitational force from the protons and neutrons in a nucleus is insignificant as an attractive force because their masses are so tiny.

This implies there must be an additional attractive force similar in size to the electrostatic repulsion which holds the nucleus together.

Learn more about stable and unstable nuclei

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Iron is a solid, grey metal. Oxygen is a colorless gas. When iron and oxygen chemically combine , rust is made. Rust has a reddi

Phoenix [80]

Because the formation of rust is a kind of chemistry reaction.
After chemistry reaction, compound with new properties is produced.
Of course, color is one of the new properties.
For example, if you put iron in colorless acid solution, a green solution is made.
This kind of chemisty reaction differs from physical reaction, for example, pigment with one color dissolves in liquid, a liquid with same color is made.

6 0

3 years ago

If a bag of peas weighs 454 grams, how many peas would be in the bag?

OverLord2011 [107]

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

The average pea weighs between 0.1 and 0.36 grams.

If we take the lower value (0.1 g/pea), the number of peas in 454 g is:

$454 g \times \frac{1pea}{0.1 g} = 4540pea$

If we take the higher value (0.36 g/pea), the number of peas in 454 g is:

$454 g \times \frac{1pea}{0.36 g} \approx 1261pea$

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

You can learn more about conversion factors here: brainly.com/question/1844638

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3 years ago

Which is the most likely to be reduced?

NISA [10]

Answer : The correct option is, $Zn^{2+}$

Explanation :

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. That means, the loss of electrons takes place.

Or we can say that, oxidation reaction occurs when a reactant losses electrons in the reaction.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. That means, the gain of electrons takes place.

Or we can say that, reduction reaction occurs when a reactant gains electrons in the reaction.

According to the electrochemical series, $Zn^{2+}$ most likely to be reduced because

Hence, the ion most likely to be reduced is $Zn^{2+}$ .

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2 years ago

What happens when The vapour obtained by dropping conc. H2SO4 in a mixture of KI and MnO2 is treated with hypo solution

Shalnov [3]

Iodine is decolorized.

The first reaction stated in the question occurs as follows;

2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)

The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.

Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.

The equation of the titration reaction is;

2Na2S2O3 + I2→ Na2S4O6 + 2NaI

When this reaction takes place, iodine is decolorized due to its reduction to I^-.

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2 years ago

2-butanone is converted into 3-methyl-3-hexanol using a grignard reagent prepared from 1-bromopropane and magnesium metal in thf

Andre45 [30]

Answer:

Here's what I get.

Explanation:

At the end of the reaction you will have a solution of the alcohol in THF.

The microdistillation procedure will vary, depending on the specific apparatus you are using, but here is a typical procedure.

Transfer the solution to a conical vial.
Add a boiling stone.
Attach a Hickman head (shown below) and condenser.
Place the assembly in in the appropriate hole of an aluminium block on top of a hotplate stirrer.
Begin stirring and heating at a low level so the THF (bp 63 °C) can distill slowly.
Use a Pasteur pipet to withdraw the THF as needed.
When all the THF has been removed, raise the temperature of the Al block and distill the alcohol (bp 143 °C).

7 0

3 years ago