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1 year ago

An element forms an oxide, E₂O₃, and a fluoride, EF₃.(a) Of which two groups might E be a member?

Chemistry

1 answer:

Fittoniya [83]1 year ago

8 0

a) The E might belong to group 13.

As the formula of a chemical compound is derived by the cross multiplication of the valency of the atoms. As formula of the given oxide is and valency of O atom is -2, therefore valency of element E must be +3 in order to obtain E2O3.

Also, in EF3, the valency of E will be +3 because there are three atoms of fluorine who has an individual valency of -1. Thus, e will have the valency of +3.

The Group 13 is the boron group which has the following elements:

Boron
Aluminium
Gallium
Indium
Thallium

All these elements have the valency of +3.

To know more about Valency, refer to this link:

brainly.com/question/12717954

#SPJ4

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From Young's experiment, how does the frequency of light affect the number of lines observed?

Marina CMI [18]

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

$dsin\theta=n\lambda$ .........(1)

n is order or number of lines observed

d is distance between slits

$\theta$ is the angle between the path and the line from screen to the slits.

We also know that, $c=\nu \lambda$

$\lambda=\dfrac{c}{\nu}$

where,

c is the speed of light

$\nu$ is frequency

$\lambda$ is wavelength

So, equation (1) turns into

$dsin\theta=n\dfrac{c}{\nu}$

$\nu=\dfrac{n\ c}{d\ sin\theta}$

So,

$\nu\propto n$

Higher frequencies have larger spaces between line.

So, correct option is (C).

3 0

2 years ago

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20 poll

aleksley [76]

Answer: n=15.56moles

Explanation:

PV = nRT

where

P is pressure in atmospheres

V is volume in Liters

n is the number of moles of the gas

R is the ideal gas constant = given as (0.0821L -atm/k-mol

PV = nRT

n= PV/RT

n= (1.5 X 230)/ (0.0821 X 270)

n= 15.56 moles

5 0

3 years ago

The reaction below demonstrates which characteristic of a base?

svlad2 [7]

Answer: option D. the ability of a base to react with a soluble metal salt.

Justification:

NaOH is a strong base, which means that in water it will dissociate according to this reaction:

NaOH(aq) → Na⁺ (aq) + OH⁻ (aq)

On the other hand, CuSO₄ is a soluble ionic salt which in water will dissociate into its ions according to this other reaction:

CuSO₄(aq) → Cu²⁺ + SO₄²⁻

Hence, in solution, the sodium ion (Na⁺) will react with the metal salt in a double replacement reaction, where the highly reactive sodium ion (Na⁺) will substitute the Cu²⁺ in the CuSO₄ to form the sodium sulfate salt, Na₂SO₄ (water soluble), and the copper(II) hydroxide, Cu(OH)₂ (insoluble).

That is what the given reaction represents:

CuSO₄ (aq) + 2NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)

↑ ↑ ↑ ↑

soluble metal salt strong base insoluble base solube salt

5 0

3 years ago

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How much heat is gained when a 50.32g piece of aluminum is heated from 9.0°c to 16°c

Rashid [163]

Answer: 317 joules

Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

C = 0.90J/g°C

Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

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3 years ago

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On the axes provided, label pressure on the horizontal axis from O mb to 760 mb and volume on the vertical axis from O to 1 mL.

Delicious77 [7]

Answer:

Please, find the graph with the labels and points located on the axes in the picture attached.

Explanation:

This is how you meet all the instructions and some important comments to understand how this kind of graphs word:

1) Label pressure on the horizontal axis from O mb to 760 mb and volume on the vertical axis from O to 1 mL.

The horizontal axis is used to record the independent variable and the vertical axis is used to record the dependent variable. The axes most be properly labeled with the name of the variable and the units.

In this case the origin is the point (0,0) which means that the axes cross each other, perpendicularly, at a pressure of 0 mb and a volume of 0.0 mililiters.

2) Assign values to axes divisions in such a way that you occupy almost all the space on both axes.

A good graph searches to occupy the whole space on both cases; to do that, find the maximum value for each variable, pressure and volume, and choose the values of the marks.

The range of the pressure (horizontal axis) is [90, 760 mb], so you should choose big divisions (marks) of 100 mb, and assign 800 mb to the right most mark on the horizontal axis. Then, you can divide each interval of 100 mb into 10 spaces, with small divisions of 10 mb (my graph uses 4 spcaes, with small divisions of 25 mb, but I recommend you use small divisions of 10 mb).

The range of the volume (vertical axis) is [0.1, 0.8], so you should choose only divisions with value of 0.1 ml.

3) Now locate and label the points:

(90, 0.9) ⇒ 90 mb, 0.9 ml

(100, 0.8) ⇒ 100 mb, 0.8 ml

(400, 0.2) ⇒ 400 mb, 0.2 ml

(600, 0.15) ⇒ 600 mb, 0.15 ml

(760, 0.1) ⇒ 760 mb, 0.1 ml

The points of the kind (x, y) are called ordered pairs, which means that the order matters, because it has a meaning: the first number represents the independent variable and the second number represents the dependent variable.

So, in the point (90, 0.9), 90 is a pressure of 90 mb and 0.9 is a volume of 0.9 ml.

To locate (600, 0.15), since the horizontal marks have value of 0.1, you must locate the second coordinate of your point between the marks 0.1 and 0.2 ml.

With that you can now locate each point on your graph.

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3 years ago

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