Explanation:
The given data is as follows.
Density of vinegar = 1.0 g/ml
Specific heat capacity = 4.25 
= 
, and 
= 
Relation between enthalpy and specific heat is as follows.
Hence, putting the values into the above formula as follows.
= 
(as density = 
)
= - 315 J
Thus, we can conclude that the enthalpy of reaction is -315 J.
As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.
It would be C!!!!!!!!!!!!!
Answer:
No, because Flourine can only form 1 bond, thus backbonding is not obtainable
Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K
Explanation :
Formula used :
where,
= change in entropy
= change in enthalpy of fusion = 3.17 kJ/mol
As we know that:
= freezing point temperature = 
Now put all the given values in the above formula, we get:
Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K
The answer is the third one because density is mass divided by volume so 80 divided by 10 is 8
