Question

The multistep smelting of ferric oxide to form elemental iron occurs at high temperatures in a blast furnace. In the first step, ferric oxide reacts with carbon monoxide to form Fe₃O₄. This substance reacts with more carbon monoxide to form iron(II) oxide, which reacts with still more carbon monoxide to form molten iron. Carbon dioxide is also produced in each step. (a) Write an overall balanced equation for the iron-smelting process.

Answer 1

Balanced equation of iron melting process

$3Fe_{2} O_{3}$ + $CO$ → $2FeO4+C_{2}$

$2Fe_{3} O_{4} + 2CO$ → $6FeO+2CO_{2}$

$6FeO +6CO$ → $6Fe+6CO_{2}$

After balancing, we get

$Fe_{2} O_{3}_{(g)} + 3CO_{(g)}$ → $3CO_{2} _{(g)} +2Fe_{(s)}$

Briefly described

Given descriptions of steps of a complex chemical reaction, we can find the overall chemical reaction by adding together the individual equation. The first step is to take our words and write them in equations, So the first reaction has a compound called ferric oxide. Feyerick is the eye on with a plus three charge, and oxide is a to minus.

So ferric oxide, the neutral compound is Effie to 03 This reacts with carbon monoxide, which is CO2 make a new compound F E 304 plus carbon dioxide, which is CO2 ,In the second step, take a product that I formed in the first and reacted with more carbon monoxide to make iron two oxide iron to means it has a charge of two plus, and again, oxide is o to minus.

So the formula is FV oh, plus carbon dioxide. Finally, the F B o reacts with carbon monoxide to form molten iron, which is just solid metal iron plus sio two. Once we have the skeleton equations, we can balance them for the first equation. I have two irons here and three irons here, so I need a three here and two here for my coefficient. This gives me six irons and six irons. I have a total of 10 oxygen's on the side and 10 oxygen's on this side and one carbon.

So the equations balanced for the second equation. Normally, I would balance it looking for the lowest whole number ratio, but in this case, I have to of these produced. So I have to balance the equation, taking that into account so it won't necessarily be the lowest whole number ratio. And in fact, the ratio is two of these with six irons here, for a total of 10 oxygen's on this side in 10 oxygen's on this side and two carbons and to carpet.

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