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kap26 [50]
2 years ago
3

Einstein's most famous equation is E = mc². In this equation, E stands for energy, m stands

Physics
1 answer:
vovangra [49]2 years ago
5 0

Answer:

m = E/c^2

Explanation:

If we solve for m, we want to get m by itself. The way to do this is divide both sides by c^2.

E/c^2 = m*c^2 / c^2

c^2 cancels out on the right side, and we are left with the following:

E/c^2 = m

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What are the potential obstacles preventing you from completing your exercises as scheduled? How can you overcome those obstacle
shusha [124]

Answer:

Sleep, behavior patterns, mental state, and job

Explanation:

3 0
3 years ago
If you ride your bike at an average speed of 2 km/h and need to travel a total distance of 20 km, how long will it take you to r
love history [14]

Answer:

Time taken to reach your destination will be 10hours

Explanation:

Recall the formula for Speed;

speed=Total distance/Total time taken

Speed=2km/h

Total distance=20km

Time taken=x

let x be the unknown time taken

Input each values into the formula;

2=20/x

Making x subject of the equation

x=20/2

x=10

Total time taken =10hours.

3 0
3 years ago
Read 2 more answers
A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk
Murrr4er [49]

Answer:

\omega_2=5.1rad/s

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is L=I\omega. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at r_2=1.39m from the center, then we have:

L_1=L_2

Or:

I_1\omega_1=I_2\omega_2

And we want to calculate:

\omega_2=\frac{I_1\omega_1}{I_2}

The total moment of inertia will be the sum of the moment of intertia of the disk of mass m_D=119.1 kg and radius r_D=3.23m, which is I_D=\frac{m_Dr_D^2}{2}, and the moment of intertia of the student of mass m_S=54.3kg at position r (which will be r_1=r=3.23m or r_2=1.39m) will be I_{S}=m_Sr_S^2, so we will have:

\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}

or:

\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}

which for our values is:

\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s

6 0
3 years ago
An air pump does 5,600 J of work to launch a water bottle rocket into the air. If the air pump applies 150 N of force to the roc
Alchen [17]

Answer: 53 m

Explanation:

Work = Force × Displacement

W= F s cosΘ

Where, s is the displacement and F is the force. Θ is the angle between force and displacement

F cosθ is the component of force acting in the horizontal direction.

The air pump applies F = 150 N force at an angle Θ = 45°

W = 5600 J

⇒s = W/F cosθ

\Rightarrow s =\frac{5600 J}{150\times cos 45^o}\approx 53 m

Thus, the horizontal distance the water bottle rocket travels is 53 m

8 0
3 years ago
Read 2 more answers
Find the Gravitational Potential at a point on the earth’s surface. Take mass of earth as 5.98 X 10 24 kg, its radius as 6.38 X
kherson [118]

Answer:

-6.25 x 10^7 J/Kg\\\\

Explanation:

The final answer is  -6.25 x 10^7 J/Kg\\\\

5 0
3 years ago
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