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Alex
3 years ago
14

A 3.5-cm radius hemisphere contains a total charge of 6.6 × 10–7

Physics
1 answer:
spayn [35]3 years ago
4 0

As per Gauss Law

Net flux through enclosed surface is

\phi = \frac{Q}{\epsilon_0}

here through this hemisphere total flux will pass through two portions

1). from the curved surface

2). from flat circular base

so now we have

\phi_{base} + \phi_{surface} = \frac{Q}{\epsilon_0}

given that

Q = 6.6 * 10^{-7} C

\phi_{surface} = 9.8 * 10^4

now we have

\phi_{base} + 9.8*10^4 = \frac{6.6*10^7}{8.85 * 10^{-12}}

\phi_{base} = - 9.8 *10^4 + 7.46 * 10^4

\phi_{base} = - 2.34 * 10^4 N*m^2/C


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