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SVETLANKA909090 [29]
2 years ago
5

The following conversion equivalents are given: 1.0 m = 100 cm 1.0 in = 2.54 cm 1.0 ft = 12 in if a bin has a volume of 1.5 m3,

the volume of the bin, in ft^3, is closest to?
Physics
1 answer:
Evgesh-ka [11]2 years ago
3 0

The volume of a bin in ft³ is closest to 53 ft³.

<h3>What is volume?</h3>

Volume is the measure of the amount of space occupied by a substance.

The formula to calculate the volume of substances varies according to the substance.

The basic unit of volume is the cubic unit of a given measurement of length.

The following conversion equivalents are given:

  • 1.0 m = 100 cm
  • 1.0 in = 2.54 cm
  • 1.0 ft = 12 in

The volume of a bin in ft³ that the volume 1.5 m³ is calculated as follows:

1 ft = 12 * 2.54 cm = 30.48 cm = 0.3048 m

1 m = 1/0.3048 ft = 3.28 ft

1.5 m³ = 1.5 * (3.281 ft)³

1.5 m³ = 52.79 ft³ ≅ 53 ft³

Learn more about volume at: brainly.com/question/28108691

#SPJ1

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The drawing shows a tire of radius R on a moving car
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Answer:

 H / R = 2/3

Explanation:

Let's work this problem with the concepts of energy conservation. Let's start with point P, which we work as a particle.

Initial. Lowest point

          Em₀ = K = 1/2 m v²

Final. In the sought height

         Em_{f} = U = mg h

Energy is conserved

        Em₀ =  Em_{f}

        ½ m v² = m g h

        v² = 2 gh

Now let's work with the tire that is a cylinder with the axis of rotation in its center of mass

Initial. Lower

        Em₀ = K = ½ I w²

Final. Heights sought

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        Em₀ =  Em_{f}

       ½ I w² = m g R

The moment of inertial of a cylinder is

       I = I_{cm} + ½ m R²

      I= ½ I_{cm}  + ½ m R²

Linear and rotational speed are related

       v = w / R

       w = v / R

We replace

      ½ I_{cm}  w² + ½ m R² w²  = m g R

moment of inertia of the center of mass      

      I_{cm}  = ½ m R²

     ½ ½ m R² (v²/R²) + ½ m v² = m gR

    m v² ( ¼ + ½ ) = m g R

   

       v² = 4/3 g R

As they indicate that the linear velocity of the two points is equal, we equate the two equations

        2 g H = 4/3 g R

         H / R = 2/3

7 0
3 years ago
A car undergoing uniform acceleration travels 100 meters from a standing start in a given period of time. If the time were incre
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Answer:

d = 1600 m

Explanation:

If car start from rest and accelerates uniformly then the displacement of the car is given as

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now we know

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now if the same car will accelerate from rest for four times of the previous time interval

then we will have

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