Answer:
  Third displacement = 2.81 m which is 61.70° north of east.
Explanation:
    Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.
   She sails 2 km east, displacement = 2 i
   Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis
   Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j
   Let third displacement be x i + y j
   We have final displacement = 5.80 km east = 5.80 i
   From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j
                                                                            = (4.47+x) i + (y - 2.47) j
   Comparing both , we have 4.47+x = 5.80
                                                         x = 1.33
                                                  y-2.47=0
                                                          y = 2.47 j
   So third displacement = 1.33 i + 2.47 j
   Magnitude of third displacement = 
   θ = tan⁻¹(2.47/1.33) = 61.70°
   So third displacement = 2.81 m which is 61.70° north of east.