The given questions belongs to the concept of limiting reagent.
The number of moles of carbon dioxide produced when 4.6 moles of dioxygen reacts is 4.6 moles.
<h3 /><h3>What is Limiting Reagent ?</h3>
The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed.
Given ;
Moles of Oxygen = 4.6
To find;
Moles of Carbon di oxide = ?
The reaction that forms 
is as follows:
C(s) + 
(g) --> (g)
This means that is consumed and is produced in a 1:1 ratio.
If we consume 4.6 mol , then we produce 4.6 mol .
Hence, 4.6 mol are produced when 4.6 mol of oxygen reacts.
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Answer:
1.33 x 10⁻³ mol/L
Explanation:
The solubility of a gas in a liquid is directly proportional to its partial pressure .This is know as Henry´s law and is given by the formula:
S(g) = Kh x P
where S = solubility of the gas
Kh = henry´s constant for the gas
P = partial pressure of the gas above solution
we are told to assume that the composition of the air in the tank is the same as on land, hence its partial pressure and we know nitrogen composition in air is 78 %, so the partial pressure of N₂ is:
P N₂ = 0.78 x 2.73 atm = 2.13 atm
Now we can calcualte the solubility as follows:
S N₂ = 6.26 x 10⁻⁴ mol / L·atm x 2.13 atm = 1.33 x 10⁻³ mol/ L
Answer:
-pneumonoultramicroscopicsilicovolcanoconiosis
-pneumonoultramicroscopicsilicovolcanoconiosis
Explanation:
