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natima [27]
2 years ago
8

Use the table on the right to calculate each required quantity

Chemistry
1 answer:
ValentinkaMS [17]2 years ago
3 0

(1) The quantity of heat required to melt 175 g Cu is 35.88 kJ.

(2) The substance that releases 21.2 kJ of energy when 1.42 mol of it freezes is iron.

<h3>What is heat of fusion?</h3>

Heat of fusion is the energy required to melt 1 mole of a substance.

<h3>What is heat of vaporization?</h3>

The heat energy required to vaporize 1 mole of a substance has been heat of vaporization.

Heat of fusion of copper (Cu) is given as 13 kJ/mol

Number of  moles of 175 g of copper = 175/63.5 = 2.76 moles

Q = nΔH

Q = 2.76 mol  x 13 kJ/mol = 35.88 kJ

Thus, the quantity of heat required to melt 175 g Cu is 35.88 kJ.

<h3>Heat of fusion of the substance</h3>

ΔH(fus) = Q/n

where;

  • n is number of moles
  • Q is quantity of heat released

ΔH(fus) = 21.2 kJ / 1.42 mol

ΔH(fus) = 14.93 kJ/mol

From the table the substance with latent heat of fusion of 14.9 kJ/mol is iron.

Thus, the substance that releases 21.2 kJ of energy when 1.42 mol of it freezes is iron.

Learn more heat of fusion here: brainly.com/question/87248

#SPJ1

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How many grams of silver chloride can be produced by reacting excess silver nitrate with 2.4 moles of zinc chloride? _____AgNO3
worty [1.4K]
<h3>Answer:</h3>

690 g AgCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u>   </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Writing Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Limiting Reactant/Excess Reactant
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] AgNO₃ + ZnCl₂ → AgCl + Zn(NO₃)₂

↓

[RxN - Balanced] 2AgNO₃ + ZnCl₂ → 2AgCl + Zn(NO₃)₂

[Given] 2.4 mol ZnCl₂

[Solve] <em>x</em> g AgCl

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol ZnCl₂ → 2 mol AgCl

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                      \displaystyle 2.4 \ mol \ ZnCl_2(\frac{2 \ mol \ AgCl}{1 \ mol \ ZnCl_2})(\frac{143.32 \ g \ AgCl}{1 \ mol \ AgCl})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 687.936 \ g \ AgCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

687.936 g AgCl ≈ 690 g AgCl

5 0
3 years ago
Consider the reaction.
Alex_Xolod [135]

Note the signs of equilibrium:-

  • Reaction don't procede forward or backward
  • Concentration of products and reactants remains same .

So

if

Concentration of A is 2M then concentration of B should be same .

So equilibrium constant K is 1

\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}

So

  • [B]=[A]^2
  • [B]=2^2
  • [B]=4M
8 0
2 years ago
Are there any vegetarian Italian Sausages?
Flura [38]
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Which of the statements below are TRUE, knowing what we know about forces and motion?
timurjin [86]

Answer:

b

Explanation:

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What is the percent of hydrogen by mass in HNO3?
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the percent of hydrogen by mass in HNO3 is 1.600%

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