One exciting fairground ride acts like a gaint catapuit. The capsule which the 'rider' is strapped in is fired high into the sky
1 answer:
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Answer:
The magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F
Explanation:
Given;
magnitude of the magnetic force is F at 14.0⁰ with respect to the field.
To determine the magnitude of the magnetic force at 32.5⁰ to the field, we apply the following formula and solve with proportion;
f*Sin(14.0⁰) = F
f*Sin(32.5⁰) = ?
Therefore, the magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F
Answer:
With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.
Explanation:
Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude .
If we have the initial velocity and its angle
, we can obtain the vertical component of the velocity
using trigonometry:
Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:
Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:
Finally, from the equation of horizontal motion with constant speed, we have that:
For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:
In words, the projectile travels 7.49m horizontally before it lands.