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Katena32 [7]
3 years ago
8

Very Important!! Electron lender or borrower?

Chemistry
2 answers:
worty [1.4K]3 years ago
4 0
Sodium lends 1 electron.
Phosphorus borrows 3 electrons.
Potassium lends one electron.
Oxygen borrows 2 electrons.
Iodine borrows one electron.
Cesium lends 1 electron.
Bromine borrows 1 electron.
Sulfur borrows 2 electrons.
And magnesium lends 2 electrons.
Paha777 [63]3 years ago
3 0

Answer : Lending makes the element as cation (positively charged species) and borrowing makes the element as anion (negatively charged species).

Usually all the metal species donates the electrons and non-metals accepts (borrows) the electrons.


Sodium (Na) donates 1 electron and becomes Na^{+}.

Phosphorus (P) accepts 3 electrons and becomes an anion of phosphorus P^{-3}.

Potassium (K) donates its one electron and gets converted to K^{+}.

Oxygen (O) accepts 2 electrons and turns as O^{-2} .

Iodine (I) accepts one electron and gets converted into I^{-}.

Cesium (Cs) donates 1 electron and turns to Cs^{+}.

Bromine (Br) accepts 1 electron and turns as Br^{-}.

Sulfur (S) accepts 2 electrons and becomes S^{-2}.

Magnesium (Mg) donates its 2 electrons and gets converted as Mn^{+2}.

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Olin [163]
This is an acid-base reaction where HF is the acid and H2O is the base (it's amphoteric and can be an acid or a base). The products would then H3O+ (the conjugate acid) and F- (the conjugate base). Now, we can simply construct a reaction using the found products and reactants. This acid-base reaction would be HF + H2O <--> H3O+ + F-.

Hope this helps!
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2 years ago
How do trends in the periodic table help predict the properties of an element
irina1246 [14]
As you move around there is a change in: electronegativies, ionisation energies, atomic radius etc. different amounts of these properties are going to effect how the element acts
8 0
2 years ago
Hi! I really really need help roght now please help me and if u put whatever in the chas as in just to get points i will ban you
dolphi86 [110]

The correct order given below shows the changes that occurs in a mice population in response to changes in their environment:

  • The population of mice is in an environment with many black rocks
  • Mice with black for are more likely to survive and reproduce than mice with brown fur
  • After many generations, most of the mice in the population have black fur
  • A sandstorm covers most of the population's environment with brown sand
  • Mice with black fur are less likely to survive and reproduce than mice with brown fur
  • After many generations, most of the mice in the population have brown fur

<h3>What is the correct order for natural selection in the desert environment given?</h3>

Based on the process of natural selection due to envrionmental pressures, the population of the mice in the desert changes as follows before and after the environmental change:

  • The population of mice is in an environment with many black rocks
  • Mice with black for are more likely to survive and reproduce than mice with brown fur
  • After many generations, most of the mice in the population have black fur
  • A sandstorm covers most of the population's environment with brown sand
  • Mice with black fur are less likely to survive and reproduce than mice with brown fur
  • After many generations, most of the mice in the population have brown fur

Therefore, the correct order shows the changes that occurs in a mice population in response to changes in their environment.

Learn more about about adaptation at: brainly.com/question/25594630

8 0
2 years ago
The molar mass of H2O is 18.01 g/mol. The molar mass of O2is 32.00 g/mol. What mass of H2O,in grams, must react to produce 50.00
N76 [4]
Answer is: mass of water is 56.28 grams.
Chemical reaction: 2H₂O → 2H₂ + O₂.
m(O₂) = 50.00 g.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 50 g ÷ 32 g/mol.
n(O₂) = 1.5625 mol.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 2 · 1.5625 mol.
n(H₂O) = 3.125 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 3.125 mol · 18.01 g/mol.
m(H₂O) = 56.28 g.
7 0
3 years ago
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I believe the correct answer is C, but I'm 100% on this.  Hope this helped though!

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