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Katena32 [7]
3 years ago
8

Very Important!! Electron lender or borrower?

Chemistry
2 answers:
worty [1.4K]3 years ago
4 0
Sodium lends 1 electron.
Phosphorus borrows 3 electrons.
Potassium lends one electron.
Oxygen borrows 2 electrons.
Iodine borrows one electron.
Cesium lends 1 electron.
Bromine borrows 1 electron.
Sulfur borrows 2 electrons.
And magnesium lends 2 electrons.
Paha777 [63]3 years ago
3 0

Answer : Lending makes the element as cation (positively charged species) and borrowing makes the element as anion (negatively charged species).

Usually all the metal species donates the electrons and non-metals accepts (borrows) the electrons.


Sodium (Na) donates 1 electron and becomes Na^{+}.

Phosphorus (P) accepts 3 electrons and becomes an anion of phosphorus P^{-3}.

Potassium (K) donates its one electron and gets converted to K^{+}.

Oxygen (O) accepts 2 electrons and turns as O^{-2} .

Iodine (I) accepts one electron and gets converted into I^{-}.

Cesium (Cs) donates 1 electron and turns to Cs^{+}.

Bromine (Br) accepts 1 electron and turns as Br^{-}.

Sulfur (S) accepts 2 electrons and becomes S^{-2}.

Magnesium (Mg) donates its 2 electrons and gets converted as Mn^{+2}.

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At 1 atm, how much energy is required to heat 75.0 g H 2 O ( s ) at − 20.0 ∘ C to H 2 O ( g ) at 119.0 ∘ C?
Hitman42 [59]

Answer:

238,485 Joules

Explanation:

The amount of energy required is a summation of heat of fusion, capacity and vaporization.

Q = mLf + mC∆T + mLv = m(Lf + C∆T + Lv)

m (mass of water) = 75 g

Lf (specific latent heat of fusion of water) = 336 J/g

C (specific heat capacity of water) = 4.2 J/g°C

∆T = T2 - T1 = 119 - (-20) = 119+20 = 139°C

Lv (specific latent heat of vaporization of water) = 2,260 J/g

Q = 75(336 + 4.2×139 + 2260) = 75(336 + 583.8 + 2260) = 75(3179.8) = 238,485 J

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