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2 years ago

A scooter is moving with a speed of 18 m/s. Its mass is 20 kg. What is the

Physics

1 answer:

kykrilka [37]2 years ago

4 0

A scooter is moving with a speed of 18 m/s. Its mass is 20 kg. What is the magnitude of its momentum?

A. 360 kg.m/s

B. 2 kg.m/s

C. 3600 kg.m/s

D. 1.1 kg.m/s

<h3>Given:-</h3>

Speed (v) of a scooter = 18 m/s

Mass (m) = 20 kg

Magnitude of its momentum (p) = ?

<h3>Answer:-</h3>

Since, we know that,

p = mv

So,

p = 20 kg × 18 m/s

p = 360 kg.m/s

<h3> $\therefore$ The correct option is (A) 360 kg.m/s </h3>

<h3>The magnitude of its momentum is <u>3</u><u>6</u><u>0</u><u> </u><u>k</u><u>g</u><u>.</u><u>m</u><u>/</u><u>s</u>. [Answer]</h3>

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Stels [109]

Answer:

628.022466 N

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Explanation:

m = Mass

$\mu$ = Coefficient of friction

t = Time taken

u = Initial velocity

v = Final velocity

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a = Acceleration

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$F_f=\mu mg\\\Rightarrow F_f=0.646\times 99.1\times 9.81\\\Rightarrow F_f=628.022466\ N$

Magnitude of frictional force is 628.022466 N

$F=ma\\\Rightarrow a=\frac{F_f}{m}\\\Rightarrow a=\frac{628.022466}{99.1}\\\Rightarrow a=6.33726\ m/s^2$

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Initial speed of the player is 8.61 m/s

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3 years ago

A proton is accelerated from rest through a potential difference of 2.5 kV and then moves perpendicularly through a uniform 0.60

Bumek [7]

Answer:

1.2cm

Explanation:

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3 years ago

Read 2 more answers

How do i find stretch? The problem in questioning has already given me the elastic energy and k-value, but I have no idea how to

finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

The expression to find the stretch (x) is $x=\sqrt{\frac{2\times EPE}{k}}$

Explanation:

Given:

Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.

To find: Elongation in the spring (x).

We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).

The formula to find EPE is given as:

$EPE=\frac{1}{2}kx^2$

Rewriting the above expression in terms of 'x', we get:

$x=\sqrt{\frac{2\times EPE}{k}}$

Example:

If EPE = 100 J and spring constant, k = 2 N/m.

Elongation or stretch is given as:

$x=\sqrt{\frac{2\times EPE}{k}}\\\\x=\sqrt{\frac{2\times 100}{2}}\\\\x=\sqrt{100}=10\ m$

Therefore, the stretch in the spring is 10 m.

So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.

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3 years ago

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maxonik [38]

Answer:

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3 years ago

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lozanna [386]

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Explanation:

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3 years ago