Wind or gravitational pull. A wave is made by friction between wind and the water’s surface. Waves can also be made by the sun and moon’s gravitational pull on the earth.
Answer:
In the morning the molecules were moving away from each other with a smaller speed than when the truck was carrying the substance.
Explanation:
Answer: 500 Watts
Explanation:
Power
is the speed with which work
is done. Its unit is Watts (
), being
.
Power is mathematically expressed as:
(1)
Where
is the time during which work
is performed.
On the other hand, the Work
done by a Force
refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path. It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (
).
When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
(2)
In this case, we have the following data:
![F=500 N](https://tex.z-dn.net/?f=F%3D500%20N)
![d=10 m](https://tex.z-dn.net/?f=d%3D10%20m)
![t=10 s](https://tex.z-dn.net/?f=t%3D10%20s)
So, let's calculate the work done by Peter and then find how much power is involved:
From (2):
(3)
(4)
Substituting (4) in (1):
(5)
Finally:
Answer:
About Transcript. Nuclear binding energy is the energy required to split an atom's nucleus into protons and neutrons. Mass defect is the difference between the predicted mass and the actual mass of an atom's nucleus. The binding energy of a system can appear as extra mass, which accounts for this difference.
Explanation:
PLZ MARK AS THE BRAINLIEST
I NEED IT URGENTLY
HAVE A GOOD DAY
MAY GOD BLESS U
: )
Answer with Explanation:
We are given that
Diameter=0.030 m
Length of sprue=
=0.200 m
Metal volume flow rate,Q=0.03![m^3/min](https://tex.z-dn.net/?f=m%5E3%2Fmin)
Q=
because 1 minute=60 seconds
Let 1 for the top and 2 for the bottom
![d_=0.030 m](https://tex.z-dn.net/?f=d_%3D0.030%20m)
![h_2=0](https://tex.z-dn.net/?f=h_2%3D0)
![A_1=\frac{\pi d^2}{4}=\frac{3.14\times (0.030)^2}{4}](https://tex.z-dn.net/?f=A_1%3D%5Cfrac%7B%5Cpi%20d%5E2%7D%7B4%7D%3D%5Cfrac%7B3.14%5Ctimes%20%280.030%29%5E2%7D%7B4%7D)
![A_1=7.065\times 10^{-4} m^2](https://tex.z-dn.net/?f=A_1%3D7.065%5Ctimes%2010%5E%7B-4%7D%20m%5E2)
![v_1=\frac{Q}{A_1}=\frac{5\times 10^{-4}}{7.065\times 10^{-4}}](https://tex.z-dn.net/?f=v_1%3D%5Cfrac%7BQ%7D%7BA_1%7D%3D%5Cfrac%7B5%5Ctimes%2010%5E%7B-4%7D%7D%7B7.065%5Ctimes%2010%5E%7B-4%7D%7D)
![v_1=0.708 m/s](https://tex.z-dn.net/?f=v_1%3D0.708%20m%2Fs)
Pressure at the top and bottom of the sprue is atmospheric
![h_1+\frac{v^2_1}{2g}=h_2+\frac{v^2_2}{2g}](https://tex.z-dn.net/?f=h_1%2B%5Cfrac%7Bv%5E2_1%7D%7B2g%7D%3Dh_2%2B%5Cfrac%7Bv%5E2_2%7D%7B2g%7D)
Substitute the values
![0.2+\frac{(0.708)^2}{2\cdot 9.8}=0+\frac[v^2_2}{2\cdot 9.8}](https://tex.z-dn.net/?f=0.2%2B%5Cfrac%7B%280.708%29%5E2%7D%7B2%5Ccdot%209.8%7D%3D0%2B%5Cfrac%5Bv%5E2_2%7D%7B2%5Ccdot%209.8%7D)
![v^2_2=2\cdot 9.8\cdot \frac{0.2\cdot 9.8\cdot 2+0.501264}{2\cdot 9.8}=4.421264](https://tex.z-dn.net/?f=v%5E2_2%3D2%5Ccdot%209.8%5Ccdot%20%5Cfrac%7B0.2%5Ccdot%209.8%5Ccdot%202%2B0.501264%7D%7B2%5Ccdot%209.8%7D%3D4.421264%20)
![v_2=\sqrt{4.421264}=2.1 m/s](https://tex.z-dn.net/?f=v_2%3D%5Csqrt%7B4.421264%7D%3D2.1%20m%2Fs)
![Q=A_2v_2](https://tex.z-dn.net/?f=Q%3DA_2v_2)
![5\times 10^{-4}=A_2\times 2.1](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E%7B-4%7D%3DA_2%5Ctimes%202.1)
![A_2=\frac{5\times 10^{-4}}{2.1}=2.381\times 10^{-4} m^2](https://tex.z-dn.net/?f=A_2%3D%5Cfrac%7B5%5Ctimes%2010%5E%7B-4%7D%7D%7B2.1%7D%3D2.381%5Ctimes%2010%5E%7B-4%7D%20m%5E2)
Reynolds number=![\frac{v_2D\rho}{\eta}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_2D%5Crho%7D%7B%5Ceta%7D)
![\eta=0.004 N.s/m^2](https://tex.z-dn.net/?f=%5Ceta%3D0.004%20N.s%2Fm%5E2)
![\rho=2700 kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D2700%20kg%2Fm%5E3)
Substitute the values then we get
Reynolds number=![\frac{2.1\times 0.03\times 2700}{0.004}](https://tex.z-dn.net/?f=%5Cfrac%7B2.1%5Ctimes%200.03%5Ctimes%202700%7D%7B0.004%7D)
Reynolds number=42525
The Reynolds number is greater than 4000 .Therefore, the flow is turbulent.