All categories

3 years ago

An object is NOT accelerating. Is its motion changing? Yes or No?

Physics

2 answers:

Alika [10]3 years ago

7 0

Answer:

Acceleration is 0. Acceleration is the change in velocity over time, so if acceleration is 0, the change in velocity is 0 no matter how much time passes. THIS DOES NOT MEAN VELOCITY IS 0. it only means that velocity is constant. In other words, the speed of motion will not change

Explanation:

Masja [62]3 years ago

5 0

Nope because if it’s not accelerating that means it’s stationary

You might be interested in

Which bird on the wire, the one with a mass of 50g or the one with a mass of 60g, has the most potential energy?

Fynjy0 [20]

Answer:

one with 60g have the more potential

Explanation:

5 0

3 years ago

How many electrons make up a charge of - 30.0 μc?

Ymorist [56]

Each electron has a charge of

$q=-1.6 \cdot 10^{-19}C$

In this problem, the total charge is

$Q=-30.0 \mu C=-30.0 \cdot 10^{-6} C$

Therefore, the number of electrons contained in this total charge will be given by the total charge divided by the charge of a single electron:

$N=\frac{Q}{q}=\frac{-30.0 \cdot 10^{-6} C}{-1.6 \cdot 10^{-19} C}=1.88 \cdot 10^{14}$

3 0

3 years ago

Read 2 more answers

A 2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to h

timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

$F_n = \frac{mv^2}{r}$

$N+mgcos\theta = \frac{mv^2}{r}$

Here,

Normal reaction of the ring is N and velocity of the ring is v

$N+mgcos\theta = \frac{mv^2}{r}$

$N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})$

$N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}$

$N = 1.374lb$

PART B) Acceleration

$F_t = ma_t$

$-mgsin\theta = ma_t$

$-W sin\theta = \frac{W}{g} a_t$

$-2Sin30\° = (\frac{2}{32.2})a_t$

$a_T = -16.10ft/s^2$

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0

3 years ago

Calculate the average speed in metres per second from Glasgow to Edinburgh

mariarad [96]

This is the same question as the one previously but with more details, so I will just use my previous answer.

1800 to 1820 is 20 minutes.1830 to 1838 is 8 minutes.1840 to 1905 is 25 minutes.
The total time travelled is 20+8+25 = 53 minutes = 3180 seconds.
The distance between Glasgow and Edinburgh is 28 + 12 + 34 = 74 km = 74000 m.

So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)

5 0

3 years ago

cylindrical container is to be constructed to be open at the top with a volume of 27π cubic meters using the least amount of mat

Llana [10]

Answer:

radius comes out to be 3 m

height of the cylinder comes out to be 3m

Explanation:

given

volume of cylinder = 27π m³

π r² h = 27π

r² h = 27.............(1)