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Phoenix [80]
4 years ago
12

A roller coaster track is a good example of the law of conservation of energy. Use this law to explain these facts about a rolle

r coaster track. a. The largest hill for a roller coaster track is the first hill on the track. The hills after the first are smaller and smaller. b. To get to the top of the first (highest) hill, a motor pulls the cars up to the top. After the top of the first hill, a motor is not needed to keep the cars going. c. The roller coaster car moves really fast at the bottom of a hill on the track but slows down as it moves up a hill (not including the first hill).
Physics
2 answers:
hammer [34]4 years ago
8 0
C. The roller coaster car moves really fast at the bottom of a hill on the track but slows down as it moves up a hill (not including the first hill).
MissTica4 years ago
4 0
The law of Conservation of Energy explains all of these observations ... a, b, and c .
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The speed of a wave is 95 m/sec. If the wavelength of the wave is 0.3 meters, what is the frequency of the wave?
Dimas [21]

<u>Answer</u>:

316.67 Hz

<u>Explanation</u>:

Given:

Wave velocity ( v ) = 95 m / sec

wavelength ( λ ) = 0.3 m

We have to calculate Frequency ( f ) :

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 95 / 0.3 Hz

= > f = 950 / 3 Hz

= > f = 316.67 Hz

Hence, frequency of sound is 316.67 Hz.

8 0
3 years ago
Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0
3 years ago
A_____ is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree celsius.
Rom4ik [11]
<span>A_____ is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree celsius.


Specific Heat Capacity of Water.
</span>
5 0
4 years ago
Read 2 more answers
A dolphin swims 1.85 km/h how far has the dolphin traveled after 0.60 h
user100 [1]

Answer:

1.11 km

Explanation:

Distance = rate × time

d = 1.85 km/h × 0.60 h

d = 1.11 km

6 0
3 years ago
What we are thinking about or are aware of at any given moment is in our?
jarptica [38.1K]
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6 0
3 years ago
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