Answer:
The answer to the question is
Its maximum speed is 1.54 m/s
Explanation:
Work done = Kinetic energy
0.5·m·v² = 0.5·k·x²
Where
m = mass
v = velocity
k = spring constant
x = extension of the spring
We note that Force F is given by
F = m·a
Where
a = acceleration due to gravity
= 0.153×9.8 = 1.4994 N
Equating the work done by the force to the work done on the spring gives
Work done = Force × Distance = 1.4994×x = 0.5×k÷x² = 0.5×24.7×x²
x = 1.4994÷12.35 = 0.121 m
Substituting the value of x into the equation below gives
0.5·m·v² = 0.5·k·x²
0.5×0.153×v² = 12.35×0.121²
v² = 0.182÷0.0765 = 2.379
v = 1.54 m/s
Answer:
Explanation:
means initial angular velocity, which is 0 rev/min
means final angular velocity, which is 
t means time t= 3.20 s
one revolution is equivalent to 2πrad so the final angular velocity is:
= (2π/60) *2.513*10^{4} rad/s
= 2628.5 rad/s
so the angular acceleration, α will be:
α = 2628.5 rad/s / 3.20 s
so the rotational motion about a fixed axis is:
+ 2αΔTita where ΔTita is the angle in radians
so now find the ΔTita the subject of the formula
ΔTita = 
Answer:
L = 4.58 x 10⁴ kg.m²/s
Explanation:
The angular momentum is given by the formula:
L = mvr
but, v = rω
Therefore,
L = mr²ω
where,
L = Angular Momentum of the person = ?
m = mass of person = 99 kg
r = radius of earth = 6.37 x 10⁶ m
ω = Angular Speed of Earth's Rotation = θ/t
Since, earth completes 1 rotation in 1 day. Hence,
ω = (2π rad/1 day)(1 day/24 h)(1 h/3600 s)
ω = 7.27 x 10⁻⁵ rad/s
Therefore,
L = (99 kg)(6.37 x 10⁶ m)²(7.27 x 10⁻⁵ rad/s)
<u>L = 4.58 x 10⁴ kg.m²/s</u>
