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inna [77]
3 years ago
11

Lamp power with what is the current through the lamp when it is connected to a battery ?

Physics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

lamp power with what is the current through the lamp when it is connected to a battery ?

Explanation:

If the light bulbs are connected in parallel, the current flowing through the light bulbs combine to form the current flowing in the battery, while the voltage drop is 6.0 V across each bulb and they all glow. One bulb burning out in a series circuit breaks the circuit.

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how many bits are required to sample an incoming signal 4000 times per second using 64 different amplitude level
Gelneren [198K]

Answer:

6 bits

Explanation:

The quality of digitized signal can be improved by reducing quantizing error. This is done by increasing the number of amplitude levels, thereby minimizing the difference between the levels and hence producing a smoother signal.

Also, Sampling frequently (also known as oversampling) can help in improving signal quality.

To get the number of bits, we use:

2ⁿ = amplitude level

where n is the number of bits.

Given an amplitude level of 64, hence:

2ⁿ = 64

2ⁿ = 2⁶

n = 6 bits

6 0
3 years ago
Substance of an atom of 2 or more elements
horrorfan [7]
H. O is the answer hope this helps
2
8 0
4 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the man

In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

6 0
3 years ago
Read 2 more answers
If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface
Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile =\frac{1}{2}mv_e^2-\frac{GMm}{R}... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, v_e=\sqrt{\frac{2GM}{R}}

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} ...(2)

(1)=(2)

⇒\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}

⇒G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2

⇒\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})

⇒\frac{h}{R+h} = \frac{3}{4}

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.  

4 0
3 years ago
Read 2 more answers
Jada was walking home for 30 mins. How fast was she walking, if her house is 4 km away fron school?
earnstyle [38]

Answer:

8 km an hour (about 5mph)

Explanation:

It depends on what you are looking for because there is no unit specified, but if you want kilometers an hour then all you have to do is multiply both sides by 2.

30 x 2 = 60 (minutes)

4 x 2 = 8 (kilometers)

Hope this helped at least a little bit!

3 0
3 years ago
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