The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
The work done on the particle is the integral of the force on dx:
So, this corresponds to the change in kinetic energy of the particle.
Answer:
62.06 g/mol
Explanation:
We are given that a solution containing 10 g of an unknown liquid and 90 g
Given mass of solute =
=10 g
Given mass of solvent=
=90 g
Freezing point of solution =-3.33
C
Freezing point of solvent =
C
Change in freezing point =Depression in freezing point
=Freezing point of solvent - freezing point of solution=0+3.33=
Hence, molar mass of unknown liquid is 62.06g/mol.
Work is (force applied) x (distance through which the force moves).
Since the suitcase doesn't move up or down during the 15 minutes,
no work is done ... zero, zip, nada ... according to the real Physics
definition of 'work'.
Answer:
Explanation:
mass, m = 1400 kg
height, h = 16 m
initial velocity, u = 21 m/s
final velocity, v = 13 m/s
Work done by engine, We = 80 kJ
Let the work done by the friction force is Wf.
Use the work energy theorem
net work done = change in kinetic energy
work done by engine + work done by friction force + work done by the gravitational force = Change in kinetic energy
80000 + Wf - m x g x h = 0.5 m ( v² - u²)
80000 + Wf - 1400 x 9.8 x 16 = 0.5 x 1400 x ( 169 - 441 )
- 139520 + Wf = - 190400
Wf = 50880 J
To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function
Here,
m = mass
a = g = Gravitational acceleration
Replacing we have that the weight is
Since the rope is taut and does not break, the net force on the rope will be zero.
Therefore the tensile force in the rope is 98N
