All categories

3 years ago

What does a star turn hydrogen into?

Physics

2 answers:

liberstina [14]3 years ago

8 0

Answer:

Helium

Explanation:

alexandr402 [8]3 years ago

6 0

Answer:

<h2>helium</h2>

As it glows, hydrogen is converted into helium in the core by nuclear fusion. The core starts to become unstable and it starts to contract. The outer shell of the star, which is still mostly hydrogen, starts to expand. As it expands, it cools and starts to glow red.

You might be interested in

The wearing down of rocks over time

RoseWind [281]

Weathering is the breaking down of rocks in a process. Deforestation is the removing of land, trees, forests for a non-forest use. Circulation is a movement that's in a cycle. Calcium carbonate is a supplement when the body lacks calcium.
Your correct answer is C.) Weathering
I hope this helps!

5 0

3 years ago

The height of an average adult person is closest to

hoa [83]

Need more info:
Gender
Where they live so u can compare to others
Ex. American white male = 5ft 10 in
Ethnicity
Etc.

4 0

3 years ago

Read 2 more answers

Listed following are several fictitious stars with their luminosities given in terms of the Sun's luminosity (LSun) and their di

vova2212 [387]

Answer:

1. Nismo: $L_{a}=0.1244$

2. Ferdinand: $L_{a}=0.0796$ , Shelby: $L_{a}=0.0796$

3. Enzo: $L_{a}=0.0398$

4. Lotus: $L_{a}=0.0199$

Explanation:

The luminosity of a star is the amount of light it emits from its surface. The luminosity is an intrinsic property of the star. Apparent brightness is how bright the star appears to a detector on Earth. Apparent brightness is not an intrinsic property of the star; it depends on the location of the observer.

As light travels towards an observer, it spreads out and covers a larger area, reducing the intensity. Thus the apparent brightness is inversely proportionate to the square of the distance between the star and observer.

Apparent brightness can be calculated by the formula below:

$L_{a}=\frac{L}{4*pi*D^{2}}$

Where, $L_{a}$ is apparent brightness, $L$ is luminosity, $D$ is the distance between the star and observer

Enzo: 200 LSun , 20 ly

$L_{a}=\frac{L}{4*pi*D^{2}}$

$L_{a}=\frac{200}{4*pi*20^{2}}$

$L_{a}=0.0398$

Ferdinand: 400 LSun , 20 ly

$L_{a}=\frac{L}{4*pi*D^{2}}$

$L_{a}=\frac{400}{4*pi*20^{2}}$

$L_{a}=0.0796$

Nismo: 100 LSun , 8 ly

$L_{a}=\frac{L}{4*pi*D^{2}}$

$L_{a}=\frac{100}{4*pi*8^{2}}$

$L_{a}=0.1244$

Lotus: 400 LSun , 40 ly

$L_{a}=\frac{L}{4*pi*D^{2}}$

$L_{a}=\frac{400}{4*pi*40^{2}}$

$L_{a}=0.0199$

Shelby: 100 LSun , 10 ly

$L_{a}=\frac{L}{4*pi*D^{2}}$

$L_{a}=\frac{100}{4*pi*10^{2}}$

$L_{a}=0.0796$

Apparent brightness of stars is summarized as below. Absolute values are considered as units are unspecified

Enzo: $L_{a}=0.0398$

Ferdinand: $L_{a}=0.0796$

Nismo: $L_{a}=0.1244$

Lotus: $L_{a}=0.0199$

Shelby: $L_{a}=0.0796$

Organized in order of apparent brightness

1. Nismo: $L_{a}=0.1244$

2. Ferdinand: $L_{a}=0.0796$ , Shelby: $L_{a}=0.0796$

3. Enzo: $L_{a}=0.0398$

4. Lotus: $L_{a}=0.0199$

5 0

3 years ago

If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.2 ss , how far do you travel during this ina

ICE Princess25 [194]

Answer: 55m

Explanation:

Given the following :

Driving speed = 90km/hr

Inattentive period (time) = 2.2s

Distance during inattentive period =

(driving speed * time)

Converting driving speed from km/hr to m/s

1000m = 1km

3600s = 1hour

Therefore,

90km/hr = (90 * 1000) / 3600

90km/hr = (90000)/ 3600 = 25m/s

Therefore ;

Distance during inattentive period =

(driving speed * time)

Distance during inattentive period = (25m/s × 2.2s) = 55m

Distance traveled during inattentive period is 55m

6 0

3 years ago

You drop a ball from the top of a building, how long does it take to reach the ground

irakobra [83]

Need more details to the question

5 0

3 years ago