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3 years ago

What is the state of matter with definite volume?

Physics

2 answers:

GenaCL600 [577]3 years ago

6 0

Solid, and liquids gases do not have volume

Sedbober [7]3 years ago

4 0

Solids and liquids have definite volumes while gases do not

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A string fixed at both ends has a length of L = 2.20 m, and a mass of m=0.0022 kg. The tension in the string is fixed at 14.30 N

PilotLPTM [1.2K]

Answer:

a) f₀ = 3250 Hz , f₁ = 6500 Hz, b) μ = 0.00100 kg/m

Explanation:

a) For standing waves to occur, waves of equal frequency that travel in opposite directions must be added

In the points where it is fixed there are nodes and in bellies or anti nodes in another symmetrical point

Fundamental wave: node at the ends, a belly (antinode in the center

L = 1 / 2 λ

Extreme node, two bellies L = 2/2 λ

For more bellies L = n / 2 λ

Therefore the equation for the wavelength is

λ = 2 L / n n = 1, 2, 3,…

Let's calculate

λ₁ = 2/1 (2.20)

λ₁ = 4.4 m

λ₂ = 2/2 2.20

λ₂ = 2.20 m

Having the wavelength we can use the relationship of wave speed and wavelength and frequency

v = λ f

v = √ T /μ

v = √ 14.30 / 0.001

v = 14300 m / s

f = v / λ

f₀ = 14300 / 4.4

f₀ = 3250 Hz

f₁ = 14300 / 2.2

f₁ = 6500 Hz

b) linear density is defined as mass per unit length

μ = m / l

μ = 0.0022 / 2.20

μ = 0.001 kg/m

5 0

4 years ago

A whale swims due east for a distance of 6.9 km, turns around and goes due west for 1.8 km, and finally turns around again and h

xeze [42]

The question is incomplete. Here is the complete question:

A whale swims due east for a distance of 6.9 km, turns around and goes due west for 1.8 km and finally turns around again and heads 3.7 km due east. (a) What is the total distance traveled by the whale? (b) What are the magnitude and direction of the displacement of the whale?

Answer:

(a) Distance = 12.4 km

(b) Displacement = 8.8 km due east

Explanation:

Consider east direction as positive and west direction as negative.

Given:

The motion is along the east-west line.

The whale first swims 6.9 km due east, then 1.8 km due west and again 3.7 km due east.

(a)

Distance traveled by the whale is equal to the sum of the lengths of all the distances traveled. Therefore,

Distance traveled = 6.9 km + 1.8 km + 3.7 km = 12.4 km

Therefore, the distance traveled by the whale is 12.4 km.

(b)

Displacement of the whale is given by considering the sign of each of the individual displacements. Therefore,

Displacement of the whale = (+6.9 km) + (-1.8 km) + (+3.7 km)

Displacement of the whale = 6.9 km - 1.8 km + 3.7 km = 8.8 km

The answer is positive. So, the direction is due east.

Therefore, the displacement of the whale is <u>8.8 km due east.</u>

6 0

4 years ago

An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his cen

iren [92.7K]

Answer:

$a=32\ m/s^2$

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2$

So, the required centripetal acceleration is $32\ m/s^2$ .

7 0

3 years ago

Could someone please tell me what I'm doing wrong?

7nadin3 [17]

Answer:

M1 = 16.9 mA

M2 = 0 A

Explanation:

As the ratio of the two sets of series resistors is almost exactly identical, there is no voltage difference across M2 to cause current flow

269/(269 + 439) = 0.3799...

500/(500 + 815) = 0.38022

M2 = 0

M1 sees only the current flowing through the far left resistors in series

A = V/R = 12/(269 + 439) = 0.016949... ≈ 16.9 mA

7 0

3 years ago

Two students have fitted their scooters with the same engine. Student A and his

sammy [17]

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

m is mass
a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

3 0

2 years ago