an electric current is a flow of electric charge in electric circuits this is carried by moving electrons in a wire and an electric circuit is an electrical network of electrical components and model of interconnection consisting electrical elements
Answer:
![v=1667.9km/h](https://tex.z-dn.net/?f=v%3D1667.9km%2Fh)
![a_{cp}=436.6km/h^2](https://tex.z-dn.net/?f=a_%7Bcp%7D%3D436.6km%2Fh%5E2)
Explanation:
The speed is the distance traveled divided by the time taken. The distance traveled in 24hs while standing on the equator is the circumference of the Earth
, where
is the radius of the Earth.
We have then:
![v=\frac{C}{t}=\frac{2\pi R}{t}=\frac{2\pi (6371km)}{(24h)}=1667.9km/h](https://tex.z-dn.net/?f=v%3D%5Cfrac%7BC%7D%7Bt%7D%3D%5Cfrac%7B2%5Cpi%20R%7D%7Bt%7D%3D%5Cfrac%7B2%5Cpi%20%286371km%29%7D%7B%2824h%29%7D%3D1667.9km%2Fh)
And then we use the centripetal acceleration formula:
![a_{cp}=\frac{v^2}{R}=\frac{(1667.9km/h)^2}{(6371km)}=436.6km/h^2](https://tex.z-dn.net/?f=a_%7Bcp%7D%3D%5Cfrac%7Bv%5E2%7D%7BR%7D%3D%5Cfrac%7B%281667.9km%2Fh%29%5E2%7D%7B%286371km%29%7D%3D436.6km%2Fh%5E2)
Answer:
The maximum height reached by the ball is 16.35 m.
Explanation:
Given;
initial velocity of the ball, u = 17.9 m/s
the final velocity of the ball at the maximum height, v = 0
The maximum height reached by the ball is given by;
v² = u² + 2gh
During upward motion, gravity is negative
v² = u² + 2(-g)h
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = (17.9)² / (2 x 9.8)
h = 16.35 m
Ttherefore, the maximum height reached by the ball is 16.35 m.