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tatuchka [14]
2 years ago
11

You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and

time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe. Where are you
Physics
1 answer:
Marta_Voda [28]2 years ago
8 0

You find yourself in a place that is unimaginably <u>hot and dense</u>. A r<u>apidly changing</u><u> gravitational field</u><u> </u>randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe, you are in the early universe before the Planck time.

<h3>What is Planck time?</h3>

The Planck time is approximately<u> 10^-44 seconds</u>. The smallest time interval, or "zeptosecond," that has so far been measured is <u>10^-21 seconds</u>. A photon traveling at the speed of light would need one Planck time <u>to traverse a distance of one </u><u>Planck length</u>.

<h3>What is Planck length?</h3>

Planck units are a set of measuring units used only in particle physics and physical cosmology. They are defined in terms of <u>four universal </u><u>physical constants</u> in such a way that when expressed in terms of these units, these physical constants have the numerical value 1. These units are a system of natural units because its definition is <u>based on characteristics of nature</u>, more especially the characteristics of free space, rather than a selection of prototype object, as was the case with Max Planck's original 1899 proposal. They are pertinent to the study of unifying theories like quantum gravity.

To learn more about Plank time:

brainly.com/question/23791066

#SPJ4

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A 1.25-kg ball begins rolling from rest with constant angular acceleration down a hill. If it takes 3.60 s for it to make the fi
miv72 [106K]

Answer:

The time taken is  \Delta t  = 1.5 \ s

Explanation:

From the question we are told that

   The mass of the ball is  m =  1.25 \ kg

    The time taken to make the first complete revolution is  t= 3.60 s

    The displacement of the first complete revolution is  \theta  =  1 rev  =  2 \pi \  radian

Generally the displacement for one  complete revolution is mathematically represented as

       \theta =  w_i t  +  \frac{1}{2} *  \alpha  * t^2

Now given that the stone started from rest w_i  = 0 \ rad / s

     2 \pi =0   +  0.5*  \alpha  *(3.60)^2

     \alpha   =  0.9698 \  s

Now the displacement for two  complete revolution is

         \theta_2  =  2 *  2\pi

         \theta_2  = 4\pi

Generally the displacement for two complete revolution is mathematically represented as  

     4 \pi =   0  +  0.5 * 0.9698 * t^2

=>   t^2  =  25.9187

=>   t=  5.1 \ s

So

 The  time taken to complete the next oscillation is mathematically evaluated as

     \Delta t  =  t_2  - t

substituting values

      \Delta t  = 5.1 -  3.60

     \Delta t  = 1.5 \ s

           

 

7 0
3 years ago
Which electrode in Thomson’s vacuum tube was positively charged
Taya2010 [7]

Anode

Explanation:

The anode in the gas discharge tube used by Thomson in his experiment was the positively charged electrode.

Using the gas discharge tube, Thomson made the remarkable discovery of cathode rays.

The rays moves from the negatively charged cathode to the positively charged anode. This indicated that the rays carry positive charges.

Some parts of the tube are:

  • Cathode - negatively charged electrode
  • Power source
  • Gas at low pressure
  • Outlet to vacuum pump

Learn more:

cathode brainly.com/question/12747250

#learnwithBrainly

8 0
3 years ago
You are loading a refrigerator weighing 2267 N onto a truck, using a wheeled cart. The refrigerator is raised 1.09 m to the truc
meriva

Answer:

a).

Wmin= 2471.03 J

W=1603.01 J

Explanation:

Weight, w= 2267 N

w= m*g\\W=m*g*h \\W=w*h

Minimum work 'h' is the distance the refrigerator is raised h=1.09m

W_{min}=2267 N* 1.09m\\W_{min}=2471.03 J

The motion is no frictional force so, the magnitude of the force with a angle of 45.0° is find using:

W=m*g*h'\\h'= sin(45)\\W=2267N*sin(45)\\W=1603.01 J

6 0
3 years ago
A joule is a unit of work is equal to ____?
Artemon [7]
Work is defined as a Newton * meter.

8 0
3 years ago
Read 2 more answers
Ejercicio 1: Un cuerpo gira en un círculo de 8cm de diámetro con una rapidez constante
Lera25 [3.4K]

Answer:

Exercise 1;

The centripetal acceleration is approximately 94.52 m/s²

Explanation:

1) The given parameters are;

The diameter of the circle = 8 cm = 0.08 m

The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m

The speed of motion = 7 km/h = 1.944444 m/s

The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²

The centripetal acceleration ≈ 94.52 m/s²

8 0
3 years ago
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