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motikmotik
3 years ago
5

The voltage between the cathode and the screen of a television set is 22 kV. If we assume a speed of zero for an electron as it

leaves the cathode, what is its speed just before it hits the screen?
Physics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

v= 8.8*10⁷ m/s

Explanation:

  • Assuming no friction present, the change in electrical potential energy, must be equal in magnitude, to the change in kinetic energy of the electron.
  • The change in the electrical potential energy, can be expressed as follows:

       \Delta U = (-e)*\Delta V

  • The change in kinetic energy, assuming that the electron started from rest, can be written as follows:

       \Delta K = \frac{1}{2} *m*v^{2}

       ⇒\Delta K = -\Delta U

  • From the equation above, replacing by ΔK and ΔU, we have:

       -\Delta U =- (-e)*\Delta V =\Delta K = \frac{1}{2} *m*v^{2}

  • Solving for v:

        v=\sqrt{\frac{2*e*\Delta V}{m_{e}} } =\sqrt{\frac{2*1.6e-19C*22e3V}{9.1e-31kg}} }\\ v= 8.8e7 m/s

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X-rays have so much energy they can go right through your ___ and ___.
Stolb23 [73]

Answer:

X-rays have so much energy they can go right through your <u>muscles</u> and <u>fat</u>.

Explanation:

There are actually more ways to fill in those two blanks... Different parts of the body absorb x-rays in varying degrees, but soft tissues (like skin, muscles, fat, and organs) allow most of the X-rays to pass through.

8 0
3 years ago
Interactive Solution 6.39 presents a model for solving this problem. A slingshot fires a pebble from the top of a building at a
mariarad [96]

(a) 29.8 m/s

To solve this problem, we start by analyze the vertical motion first. This is a free fall motion, so we can use the following suvat equation:

v_y^2 - u_y^2 = 2as

where, taking upward as positive direction:

v_y is the final vertical velocity

u_y = 0 is the initial vertical velocity (zero because the pebble is launched horizontally)

a=g=-9.8 m/s^2 is the acceleration of gravity

s = -25.0 m is the displacement

Solving for vy,

v_y = \sqrt{u^2+2as}=\sqrt{0+2(-9.8)(-25)}=-22.1 m/s (downward, so we take the negative solution)

The pebble also have a horizontal component of the velocity, which remains constant during the whole motion, so it is

v_x = 20.0 m/s

So, the final speed of the pebble as it strikes the ground is

v=\sqrt{v_x^2+v_y^2}=\sqrt{20.0^2+(-22.1)^2}=29.8 m/s

(b) 29.8 m/s

In this case, the pebble is launched straight up, so its initial vertical velocity is

u_y = 20.0 m/s

So we can find the final vertical velocity using the same suvat equation as before:

v_y^2 - u_y^2 = 2as

v_y = \sqrt{u^2+2as}=\sqrt{(20.0)^2+2(-9.8)(-25)}=-29.8 m/s (downward, so we take the negative solution)

The horizontal speed instead is zero, since the pebble is initially launched vertically, so the final speed is just equal to the magnitude of the vertical velocity:

v = 29.8 m/s

(c) 29.8 m/s

This case is similarly to the previous one: the only difference here is that the pebble is launched straight down instead than up, therefore

u_y = -20.0 m/s

Using again the same suvat equation:

v_y^2 - u_y^2 = 2as

v_y = \sqrt{u^2+2as}=\sqrt{(-20.0)^2+2(-9.8)(-25)}=-29.8 m/s (downward, so we take the negative solution)

As before, the horizontal speed instead is zero, since the pebble is initially launched vertically, so the final speed is just equal to the magnitude of the vertical velocity:

v = 29.8 m/s

We notice that the final value of the speed is always the same in all the three parts, so it does not depend on the direction of launching. This is due to the law of conservation of energy: in fact, the initial mechanical energy of the pebble (kinetic+potential) is the same in all three cases (because the height h does not change, and the speed v does not change either), and the kinetic energy gained during the fall is also the same (since the pebble falls the same distance in all 3 cases), therefore the final speed must also be the same.

7 0
3 years ago
8. What is the mass of an object if a force of 34 N produces an acceleration of 4 m/s/s?
coldgirl [10]

Answer:

<h3>The answer is 8.5 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

where

f is the force

a is the acceleration

So we have

m =  \frac{34}{4}  =  \frac{17}{2}  \\

We have the final answer as

<h3>8.5 kg</h3>

Hope this helps you

7 0
3 years ago
Read 2 more answers
Which of the following is not a popular surface for a tennis court?
vovikov84 [41]

The answer is A. wood

because there are three different courts: clay court, grass court, and hard court. wood isn't in there so that would be the answer.

8 0
3 years ago
While a roofer is working on a roof that slants at 39.0 degrees above the horizontal, he accidentally nudges his 88.0 N toolbox,
Ostrovityanka [42]

Answer:

V= 6.974 m/s

Explanation:

Component( box) weight acting parallel and down roof 88(sin39.0°)=55.4 N

Force of kinetic friction acting parallel and up roof = 18.0 N

Fnet force acting on tool box acting parallel and down roof

Fnet= 55.4 - 18.0

Fnet=37.4 N

acceleration of tool box down roof

a = 37.4(9.81)/88.0

a= 4.169 m/s²

d = 4.90 m

t = √2d/a

t= √2(4.90)/4.169

t= 1.662 s

V = at

V= 4.169(1.662)

V= 6.974 m/s

5 0
3 years ago
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