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4 years ago

According to a relatively recent discovery which member of the solar system has one satellite

2 answers:

7 0

The planet of Pluto has been one of the most mysterious planet the solar system has now. It has been classified as a dwarf planet, in which it is only considered as a minor planet, and removed to the major planets already. In addition to that, it was also recently discovered that the planet could have only 1 moon revolving through it instead of the usual 2 satellites.

Grace [21]4 years ago

7 0

<h3><u>Question:</u></h3>

<u>According to a relatively recent discovering which member of the solar system has one satellite?</u>

<h3><u>Answer:</u></h3>

<u>the planet that has one satellite recent discovery would have been Pluto</u>

<h3><u>Pluto's moons:</u></h3>

<u>Charon</u>

Hope this helps u

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If you started the motor of a boat in the middle of a lake, who would detect the sound of the motor first: a friend sitting on t

ArbitrLikvidat [17]

Answer:

A friend snorkeling just below the surface of the water along the same shore will detect the sound first.

Explanation:

The speed of sound in water medium is faster than that through the air.
Sound propagates through the medium by transferring through the molecules on it. Water has more closely packed molecules due to which the speed is faster.
In fact, the sound's speed in water is almost four times faster than that in the air.
So the guy in the water surface gets to hear sound faster than the one in sore.

6 0

4 years ago

Read 2 more answers

Two masses —m1 and m2— are connected by light cables to the perimeters of two cylinders of radii r1 and r2 respectively, as show

Aleksandr [31]

Answer:

Part a)

Mass of m2 is given as

$m_2 = \frac{20}{3} kg$

Part b)

Angular acceleration is given as

$\alpha = 1.96 rad/s^2$

Part c)

Tension in the rope is given as

$T = 176.6 N$

Explanation:

Part a)

When m1 and m2 both connected to the cylinder then the system is at rest

so we can use torque balance here

$m_1g r_1 = m_2 g r_2$

$20 g(0.5) = m_2 g(1.5)$

$10 = 1.5 m_2$

$m_2 = \frac{20}{3} kg$

Part b)

When block m_2 is removed then system becomes unstable

so force equation of mass m1

$m_1g - T = m_1 a$

also we have

$T r_1 = I\alpha$

now we have

$m_1g = \frac{I a}{r_1^2} + m_1 a$

$a = \frac{m_1g}{\frac{I}{r_1^2} + m_1}$

$a = \frac{20 (9.81)}{\frac{45}{0.5^2} + 20}$

$a = 0.981 m/s^2$

so angular acceleration is given as

$\alpha = \frac{a}{r_1}$

$\alpha = \frac{0.981}{0.5}$

$\alpha = 1.96 rad/s^2$

Part c)

Tension in the rope is given as

$T = \frac{I\alpha}{r_1}$

$T = \frac{45 (1.96)}{0.5}$

$T = 176.6 N$

7 0

3 years ago

an empty propane tank dropped from a hot air balloon hits the ground with a speed of 143.8 m/s. from what height was the tank re

vodomira [7]

What you know:
Vi=0m/s
Vf=143.8m/s
A=-9.8m/s
d=???
Use the equation Vf^2=Vi^2+2A(d)
Rearrange to isolate d: d=Vf^2/2A
d=(143.8)^2/2(-9.8)
d=20678.4/-19.6
d=-1055m
The tank was released from a height of 1055m

8 0

3 years ago

A uranium nucleus is traveling at 0.94 c in the positive direction relative to the laboratory when it suddenly splits into two p

Anettt [7]

Answer:

A u = 0.36c B u = 0.961c

Explanation:

In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains

u ’= (u-v) / (1- uv / c²)

Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory

The data give is u ’= 0.43c and the initial core velocity v = 0.94c

Let's clear the speed with respect to the observer (u)

u’ (1- u v / c²) = u -v

u + u ’uv / c² = v - u’

u (1 + u ’v / c²) = v - u’

u = (v-u ’) / (1+ u’ v / c²)

Let's calculate

u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)

u = 0.51c / (1 + 0.4042)

u = 0.36c

We repeat the calculation for the other piece

In this case u ’= - 0.35c

We calculate

u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)

u = 1.29c / (1- 0.329)

u = 0.961c

6 0

3 years ago

When a photon collides with an electron and is deflected, the photon’s ____ decreases.

masha68 [24]

Answer:

2. Wavelength

Explanation:

When a photon collides with an electron and is deflected, the photon’s wavelength decreases.

When photon gained energy by the collision of the electron. Its energy and frequency will be increased and its wavelength will be decreased.

7 0

3 years ago

Read 2 more answers