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dusya [7]
2 years ago
8

To which end of the horseshoe magnet will the north end of the magnet be attracted

Physics
1 answer:
Scrat [10]2 years ago
7 0

Answer:

The north end of the  magnet will be attracted to the south end of the horseshoe magnet.

Likewise, the north end of the magnet will be attracted to the earth's north pole - so the north pole of the earth is actually a south magnetic pole.

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Sabrina decided to start selling lemonade on her street. The other kids in the neighborhood noticed that Sabrina was making a lo
suter [353]

Answer:

e. Decreased; Increased

Explanation:

The market equilibrium refers to the condition in which the price and the quantity are in equilibrium if the conditions of supply (what the producers offer) and demand (what the consumers buy) don't change.

In this case we have that as the other kids decide to sell more lemonade the amount of lemonade is going to increase (equilibrium quantity) and because of this the price is going to decrease (equilibrium price).

Then when the other kids open theirown lemonade stand, the equilibrium price <u>descreased</u> and the equilibrium quantity <u>increased.</u>

6 0
3 years ago
Can someone tell me the answer to this?
Art [367]

Answer:

A

Explanation:

5 0
2 years ago
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Which statement explains what happens to older crust during seafloor spreading?
ikadub [295]

Answer:

the last one, It moves away from a mid-ocean ridge.

6 0
2 years ago
PLEASE HELP!!!
Arisa [49]

Answer:

Each type of electromagnetic radiation have been matched to their descriptions as follows:

Ultraviolet light A) Given off by very hot objects, such as the sun

Gamma rays B) Given off by radioactive substances  

Microwaves C) Used in radar and to heat food

X‒rays D) Used in the medical field to see bone structure

Explanation:

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6 0
3 years ago
The ink drops have a mass m = 1.00×10^−11 kg each and leave the nozzle and travel horizontally toward the paper at velocity v =
luda_lava [24]

Answer:

9.98 × 10⁻⁹ C

Explanation:

mass, m = 1.00 × 10⁻¹¹ kg

Velocity, v = 23.0 m/s

Length of plates D₀ = 1.80 cm = 0.018 m

Magnitude of electric field, E = 8.20 × 10⁴ N/C

drop is to be deflected a distance d = 0.290 mm = 0.290 × 10⁻³ m

density of the ink drop = 1000 kg/m^3

Now,

Time = \frac{\textup{Distance}}{\textup{Velocity}}

or

Time = \frac{\textup{0.016}}{\textup{23}}

or

Time = 6.9 × 10⁻⁴ s

Now, force due to the electric field, F = q × E

where, q is the charge

Also, Force = Mass × acceleration

q × E = 1.00 × 10⁻¹¹ × a

or

a = \frac{q\times8.20\times10^4}{1\times10^{-11}}

Now from the Newton's equation of motion

d=ut+\frac{1}{2}at^2

where,  

d is the distance

u is the initial speed  

a is the acceleration

t is the time

or

0.290\times10^{-3}=0\times(6.9\times10^{-4})+\frac{1}{2}\times(\frac{q\times8.20\times10^4}{1\times10^{-11}})\times(6.9\times10^{-4})^2

or

q = 9.98 × 10⁻⁹ C

4 0
3 years ago
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