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almond37 [142]
3 years ago
14

A sphere has a mass of 8.5 kg and a radius of 10cm. How much work is it necessary to do on the ball to get it to a speed of 6.0m

/s?
Physics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

<h2>153J</h2>

Explanation:

Step one:

given data

mass m= 8.5kg

radius r= 10cm in meters = 0.01m

velocity v= 6m/s

The work done will be the same as the energy possessed by the sphere at such speed

Required

the work one in Joules

we know that

KE=1/2mv^2

KE=1/2*8.5*6^2

KE= 1/2*8.5*36

KE=306/2

KE=153J

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a

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a hotgas is injected into at engine at 573 k and exhausts at 343 k. what is the highest efficiency of thisengine?
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4 0
3 years ago
a vehicle starts from rsst and after 10 seconds its velocity is 20m/s find the acceleration and the distance travelled.(step by
Naily [24]

Answer:

<u>Acceleration is 2 m/s² </u>

<u>Distance</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>m</u>

Explanation:

From definition of acceleration, Acceleration is the rate of change in velocity.

• Simplifying the definition, or modifying it;

{ \boxed{ \rm{acceleration =  \frac{(final \: velocity - initial \: velocity)}{time} }}}

• Let's formulate symbols:

{ \boxed{ \rm{a =  \frac{v - u}{t} }}}

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  • u is initial velocity, u = 0 m/s [ at rest ]
  • t is time, t = 10 seconds

{ \rm{a =  \frac{20 - 0}{10}  =  \frac{20}{10} }} \\  \\{ \boxed{ \rm{ \: a = 2 \:  {ms}^{ - 2} }}}

Distance = ut + ½at²

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Distance = 0 + 10²

Distance = 100 meters

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2 years ago
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