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almond37 [142]
3 years ago
14

A sphere has a mass of 8.5 kg and a radius of 10cm. How much work is it necessary to do on the ball to get it to a speed of 6.0m

/s?
Physics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

<h2>153J</h2>

Explanation:

Step one:

given data

mass m= 8.5kg

radius r= 10cm in meters = 0.01m

velocity v= 6m/s

The work done will be the same as the energy possessed by the sphere at such speed

Required

the work one in Joules

we know that

KE=1/2mv^2

KE=1/2*8.5*6^2

KE= 1/2*8.5*36

KE=306/2

KE=153J

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lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

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  • m₂: is the <em>mass </em>of the object dropped = 2 kg
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  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

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15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

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