Question

calcium is obtained industrially by electrolysis of molten cacl2 and is used in aluminum alloys. how many coulombs are needed to produce 20.2 g of ca metal? if a cell runs at 15 a, how many minutes will it take to produce 20.2 g of ca(s)? × 10 coulombs (enter your answer in scientific notation.) minutes

Answer 1

It takes 107 minutes 22 seconds and 96500 coulombs of charge produce 20.2 g of calcium.

The balanced equation for the reaction is,

$CaCl _{2} \:→ \: Ca ^{ 2 + } + 2Cl {}^{ - }$

The half-reaction of calcium is,

$Ca ^{2 + } + 2e ^{ - } → \: Ca$

Mass of calcium = 20.2 g

The molecular mass of calcium = 40 u.

The number of moles calcium are,

$Number \: of \: moles = \frac{mass}{molecular \: mass}$

$= \frac{20.2}{40}$

$= 0.5 \: moles$

One mole of Calcium is produced by 2 moles of electrons.

So, 0.5 moles of Calcium produce,

$= 0.5 \times 2$

$= 1 \: mole \: of \: electron$

The charge required to produce 202 g of calcium is,

$= 1 \:F$

$= 1 \times 96500 \: C$

$= 96500 \: C$

Current = 15 A

The time taken to produce 20.2 g of calcium is,

$I = \frac{Q}{T}$

$T = \frac{96500}{15}$

$= 6433.3 \: s$

$= 107 \: minutes \: 22 \: seconds$

Therefore, 96500 columns of charge are required to produce 20.2 grams of calcium. And it takes 107 minutes and 22 seconds.

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