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2 years ago

The nebular theory also predicts that the cloud should heat up as it collapses. what physical law explains why it heats up?

1 answer:

4 0

The physical law that explains that is the law of conservation of energy which states that he energy of an isolated sistem remains constant

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You decide to impress Grandpa by showing him how fast sound travels. You have a piece of plastic pipe with an adjustable closed

fredd [130]

Answer:

336.96m/s

Explanation:

answer is in photo above

3 0

2 years ago

If a steel cylindrical specimen is stressed nominally to 53 MPa, what stress level exists at the tip of an elliptical surface fl

ElenaW [278]

Answer:

227.9MPa

Explanation:

Length of the flaws is given by

2b = 5.8microns

b = 2.9 × 10⁻⁶m

The relation between the radius of curvature and length and width of the elliptical flaw

$r = \frac{a^2}{b}$

$a = \sqrt{rb}$

Equation for stress at the tip of an elliptical surface flaw

$\sigma _t = \sigma(1 + 2\frac{b}{a} )\\\\\sigma _t = \sigma(1 + 2\frac{b}{\sqrt{rb} })\\\\\sigma _t = \sigma(1 + 2\frac{\sqrt{b} }{\sqrt{r} })\\\\\sigma _t = \sigma(1 + 2\sqrt{\frac{b}{r} })$

$\sigma _t = 53 \times 10^6 (1 + 2\sqrt{\frac{2.9\times10^-^6 }{1065 \times 10^-^9} } \\\\\sigma _t = 227.9 \times 10^6\\\\\sigma _t = 227.9MPa$

4 0

2 years ago

A certain freely falling object, released from rest, requires 1.95 s to travel the last 23.5 m before it hits the ground. (a) Fi

Ratling [72]

Answer:

(a). The velocity of the object is -2.496 m/s.

(b). The total distance of the object travels during the fall is 23.80 m.

Explanation:

Given that,

Time = 1.95 s

Distance = 23.5 m

(a). We need to calculate the velocity

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$-23.5=u\times1.95+\dfrac{1}{2}\times(-9.8)\times(1.95)^2$

$u=\dfrac{-23.5+4.9\times(1.95)^2}{1.95}$

$u=-2.496\ m/s$

(b). We need to calculate the total distance the object travels during the fall

Using equation of motion

$v = u+gt$

Put the value in the equation

$-2.496=0-9.8\times t$

$t =\dfrac{2.496}{9.8}$

$t=0.254\ sec$

The total time is

$t'=t+1.95$

$t'=0.254+1.95$

$t'=2.204\ sec$

We need to calculate the distance

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times9.8\times(2.204)^2$

$s=23.80\ m$

Hence, (a). The velocity of the object is -2.496 m/s.

(b). The total distance of the object travels during the fall is 23.80 m.

4 0

2 years ago

A rolling ball with a mass of 1.01 kg crashes into a wall. The wall exerts a force of 2.40 Newtons and stops the ball. What was

klemol [59]

Answer:

Acceleration, a = 2.38m/s²

Explanation:

Given the following data;

Mass = 1.01 kg

Force = 2.4N

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

$Acceleration, a = \frac{F}{m}$

Substituting into the equation, we have;

$Acceleration, a = \frac{2.4}{1.01}$

<em>Acceleration, a = 2.38m/s²</em>

<em>Therefore, the magnitude of the acceleration of the ball at the time of the crash is 2.38 meters per seconds square. </em>

3 0

2 years ago

What are glacial episodes example of

il63 [147K]

Glacial episodes are examples of positive feedbacks

6 0

3 years ago

Read 2 more answers