Ask question

Ask question

All categories

3 years ago

9

If B is added to C, the result is a vector in the direction of the positive y-axis with a magnitude equal to that of If C = zi +

yj, where x=6.13 and y=7.12 what is the magnitude of B?

1 answer:

fredd [130]3 years ago

4 0

Answer:c

Explanation:

You might be interested in

From January 26, 1977, to September 18, 1983, George Meegan of Great Britain walked from Ushuaia, at the southern tip of South A

Nikolay [14]

Answer:

0.146 m/s

Explanation:

We can see it in the pic.

3 0

2 years ago

In refraction, when a wave travels from one medium to another, it

kirill115 [55]

In refraction, when a wave travels from one medium to another it changes speed.

Correct option is A.

3 0

3 years ago

Read 2 more answers

In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively

Elanso [62]

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

8 0

2 years ago

You're driving a vehicle of mass 1350 kg and you need to make a turn on a flat road. The radius of curvature of the turn is 71 m

sergey [27]

Answer:

$v=12.65\ m.s^{-1}$

Explanation:

Given:

mass of vehicle, $m=1350\ kg$

radius of curvature, $r=71\ m$

coefficient of friction, $\mu=0.23$

<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>

$m.\frac{v^2}{r} =\mu.N$

where:

$\mu=$ coefficient of friction

$N=$ normal reaction force due to weight of the car

$v=$ velocity of the car

$1350\times \frac{v^2}{71} =0.23\times (1350\times 9.8)$

$v=12.65\ m.s^{-1}$ is the maximum velocity at which the vehicle can turn without skidding.

5 0

3 years ago

A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before

nadya68 [22]

Answer:

Explanation:

Given

mass of steel ball $m=0.2\ kg$

initial speed of ball $u=10\ m/s$

Final speed of ball $v=-10\ m/s$ (in upward direction)

Impulse imparted is given by change in the momentum of object

therefore impulse J is given by

$J=\Delta P$

$\Delta P=m(v-u)$

$\Delta P=0.2(-10-10)$

$\Delta =-4\ N-s$

so magnitude of Impulse =4 N-s

7 0

2 years ago

Read 2 more answers