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Marrrta [24]
3 years ago
13

10 uses of non-metals​

Chemistry
1 answer:
Grace [21]3 years ago
3 0

Answer: 10 uses

Explanation:

1] Oxygen is used for breathing.

2] Chlorine is used for purifying water.

3] Phosphorous is used in crackers.

4] Non - metals like nitrogen is used in fertilizers.

5] Graphite is used as a good conductor of electricity.

6] Pottassium is used in fertilizers.

7] Nitrogen is used by plants.

8] Graphite is used in making leads.

9] Carbon is used as a fuel.

10] Bromine is used in dyes and pesticides

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How much heat is absorbed by 0.060 kg of copper when it is heated from 20.0°C to 80.0°C if the specific heat of copper is 385J/k
Elina [12.6K]

Answer:

its 1386J

Explanation:

7 0
3 years ago
Which isomer of 1-bromo-2-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?Draw the structure of t
ivolga24 [154]

Answer:

See explanation and image attached

Explanation:

The reaction of 1-bromo-2-tert-butylcyclohexane with  potassium tert-butoxide is an elimination reaction that occurs by E2 mechanism.

The E2 reaction proceeds faster when the hydrogens are in an antiperiplanar position at an angle of 180 degrees.

This is only attainable in the trans isomer of 1-bromo-2-tert-butylcyclohexane. Hence trans 1-bromo-2-tert-butylcyclohexane reacts faster with potassium tert-butoxide

8 0
3 years ago
How many moles are in 35.0 grams of H₂O?
Nikitich [7]
1.94 moles


I did 35/18.02 because 18.02 is the molar mass of water
3 0
3 years ago
Model describe how you would show j.j. thomson's model of the atom using small beads and clay
faltersainse [42]
Make a ball of clay and embed small beads throughout it. The plum pudding model.
5 0
3 years ago
Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---> 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
3 years ago
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