They differ in their molecular structures and properties.
Answer:
9.80 g
Explanation:
The molecular mass of the atoms mentioned in the question is as follows -
S = 32 g / mol
F = 19 g / mol
The molecular mass of the compound , SF₆ = 32 + ( 6 * 19 ) = 146 g / mol
The mass of 6 F = 6 * 19 = 114 g /mol .
The percentage of F in the compound =
mass of 6 F / total mass of the compound * 100
Hence ,
The percentage of F in the compound = 114 g /mol / 146 g / mol * 100
78.08 %
Hence , from the question ,
In 12.56 g of the compound ,
The grams of F = 0.7808 * 12.56 = 9.80 g
Answer:
Plants use photosynthesis to make glucose. Glucose is also know as sugar. You can tell it is present if the plant receives sunlight as well as water.
Explanation:
MARK BRAINLIEST
<h2>Answer and Explanation </h2>
The body of water means the occurrence of water on earth’s surface. Examples are oceans, lakes, seas, ponds, and pools. The major bodies of water are:
- Pacific ocean is the biggest and deepest of Earth's oceanic divisions. It stretches from the Arctic Ocean in the direction to the Southern Ocean.
- Atlantic ocean is another giant of the world's oceans. It includes nearly 20 percent of the Earth's exterior and nearly 29 percent of its water covering space.
- The Indian Ocean is the third largest Ocean in the world. It is surrounded by Asia, Africa, and Australia.
- Arctic ocean is the smallest and shallowest of the world's five main oceans.
- Mediterranean sea is a sea is attached to the Atlantic Ocean.
Answer:
Uranium must be purified before it is used as a fuel source
Explanation:
The purer the uranium sample, the more the concentration of uranium in the fuel is.
Whenever uranium is extracted from nature, it contains a lot of impurities. Only a few special nuclear reactors can utilize uranium in this raw state. most of the others have to get uranium to become about 3% pure before they begin using it.
To do this, uranium has to be passed through a series of chemical reactions all with the aim of extracting the other compounds that may be present in the fuel.
