Increasing the temperature of gas will probably ruin whatever it’s in. Such as a car, the increase of temperature will ruin the car price by peice.
Answer:
Approximately 
.
Explanation:
The Lyman Series of a hydrogen atom are due to electron transitions from energy levels 
to the ground state where 
. In this case, the electron responsible for the line started at 
and transitioned to
A hydrogen atom contains only one electron. As a result, Bohr Model provides a good estimate of that electron's energy at different levels.
In Bohr's Model, the equation for an electron at energy level 
(
(note the negative sign in front of the fraction,)
where
is a constant.
is the atomic number of that atom. 
for hydrogen.- is the energy level of that electron.
The electron that produced the line was initially at the
.
The electron would then transit to energy level . Its energy would become:
.
The energy change would be equal to
.
That would be the energy of a photon in that spectrum line. Planck constant 
relates the frequency of a photon to its energy:
, where
is the energy of the photon.
is the Planck constant.
is the frequency of that photon.
In this case, 
. Hence,
.
Note that 
.
(D) At equilibrium, the concentration of the products will be much higher than the concentration of the reactants.
A is true of UV rays.
B is true not of UV rays but rather of visible light.
C is true not of UV rays but rather of microwaves. (unless you actually toast your toast in a toaster like a normal person)
D is true not of UV rays but rather of radio waves.
Answer:
a. 0.27 = Kc
b. 8.19×10⁻⁵ = Kp
Explanation:
The reaction is this: 3H₂(g) + N₂ (g) ⇄ 2NH₃ (g)
As we have the moles of each in the equilibrium and the volume is 1L, we assume the concentrations as molarity.
1.6981 mol/L → H₂
0.5660 mol/L → N₂
0.8679 mol/L → NH₃
Let's make the expression for Kc
Kc = [NH₃]² / [N₂] . [H₂]³
Kc = 0.8679² / 0.5660 . 1.6981³
Kc = 0.27
Let's calculate Kp, derivated from Kc
Kp = Kc . (RT)^Δn where:
Δn is the difference between final moles - initial moles. It is governed by stoichiometry. For this case 2 - (1+3) = -2
Δn it is always for gases
R is the Ideal gases constant
T is Absolute T°
Let's replace data → 0.27 . (0.082 . 700K)⁻² = Kp
8.19×10⁻⁵ = Kp
