First, consider the steps to heat the sample from 209 K to 367K.
1) Heating in liquid state from 209 K to 239.82 K
2) Vaporaizing at 239.82 K
3) Heating in gaseous state from 239.82 K to 367 K.
Second, calculate the amount of heat required for each step.
1) Liquid heating
Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol
=> number of moles = 12.62 g / 17 g/mol = 0.742 mol
Heat1 = #moles * heat capacity * ΔT
Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J
2) Vaporization
Heat2 = # moles * H vap
Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J
3) Vapor heating
Heat3 = #moles * heat capacity * ΔT
Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J
Third, add up the heats for every steps:
Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J
Fourth, divide the total heat by the heat rate:
Time = 22,466.3 J / (6000.0 J/min) = 3.7 min
Answer: 3.7 min
Answer:
It should be 1. 1.2 X 10^24
Explanation:
Hello!
According to the
Charles' Law, the volume of a gas is proportional to temperature when pressure is constant. When going from New York to Florida, if the pressure is left constant
the volume of the tires will increase.The final volume of the tires can be calculated from the following equation, derived from Charles' Law:
Have a nice day!
Answer:
the correct answer is 17 significant figures
Answer:
The correct answer is option c. transfer of electrons from Mg to O.
Explanation:
Hello!
Let's solve this!
When Magnesium (Mg) reacts with oxygen (O), magnesium oxide is formed.
This reaction is spontaneous and occurs with oxidation number +2 of magnesium and oxidation number -2 of oxygen. It is an ionic union, so magnesium transfers its electrons to oxygen.
We conclude that the correct answer is option c. transfer of electrons from Mg to O.
