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Nana76 [90]
3 years ago
15

Addition of dns at the end of the incubation period stopped the reaction by denaturing sucrase. explain why it is important to d

enature sucrase before measuring product concentration
Chemistry
2 answers:
bixtya [17]3 years ago
7 0
Answer is: i<span>t is important to denature sucrase before measuring product concentration because if sucrase is active that will increase the enzyme activity and lower concentration of sugar.
DNS (</span>3,5-dinitrosalicylic acid)<span> is an </span>aromatic compound<span> that reacts with </span><span>reducing sugars.</span><span>

</span>
STatiana [176]3 years ago
5 0

Answer:

It might react with the product and consequently lower its concentration.

Explanation:

Hello,

When adding dna, we must assure the denaturing of sucrase as it could react with the product and lower its final concentration. Moreover, non-denatured sucrase spurs on the enzymatic activity which also would affect the final product resulting concentration, that is why we must guarantee the complete denaturing of the sucrase.

Best regards.

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3 years ago
What information is needed to determine the energy of an electron in a many-electron atom? a) n. b) l. c) ml. d)ms
mel-nik [20]

Answer:

The correct answer is b.

Explanation:

The quantum number n specifies the energetic level of the orbital, the first level being the one with the least energy. As n increases, the probability of finding the electron near the nucleus decreases and the orbital energy increases.

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8 0
3 years ago
Read 2 more answers
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = T_1=33.9^oC=33.9+273K=306.9 K

Final temperature of the water = T_2

Specific heat capacity of water under these conditions =  c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)

-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC

The new temperature of the water bath 32.0°C.

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