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Nana76 [90]
3 years ago
15

Addition of dns at the end of the incubation period stopped the reaction by denaturing sucrase. explain why it is important to d

enature sucrase before measuring product concentration
Chemistry
2 answers:
bixtya [17]3 years ago
7 0
Answer is: i<span>t is important to denature sucrase before measuring product concentration because if sucrase is active that will increase the enzyme activity and lower concentration of sugar.
DNS (</span>3,5-dinitrosalicylic acid)<span> is an </span>aromatic compound<span> that reacts with </span><span>reducing sugars.</span><span>

</span>
STatiana [176]3 years ago
5 0

Answer:

It might react with the product and consequently lower its concentration.

Explanation:

Hello,

When adding dna, we must assure the denaturing of sucrase as it could react with the product and lower its final concentration. Moreover, non-denatured sucrase spurs on the enzymatic activity which also would affect the final product resulting concentration, that is why we must guarantee the complete denaturing of the sucrase.

Best regards.

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Based on the context of paragraph 4, what are salient factors?
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importent factors

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The salient facts about something or qualities of something are the most important things about them: She began to summarize the salient features/points of the proposal. The article presented the salient facts of the dispute clearly and concisely. SMART Vocabulary: related words and phrases. Very important or urgent.

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What is the molarity of a solution in which 0.732 moles of hcl are dissolved in 0.975 liters of solution?
posledela
Molarity is moles divided by liters so do .732 divided by .975 liters.
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A student combines 20.0 grams of hydrogen and 20.0 grams of oxygen in a reaction. According to the law of conservation of mass,
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A)20.0grams

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In which of the following phases of matter do molecules have the lowest amount of energy?
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Answer:

C. Solid

Explanation:

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4 years ago
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Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and
Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%

Then,

Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%

Percent\ yield\ of\ copper\ hydroxide= 84\%

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

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