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Mkey [24]
3 years ago
8

A loudspeaker in a parked car is producing sound whose frequency is 20950 Hz. A healthy young person with normal hearing is stan

ding nearby on the sidewalk but cannot hear the sound because the frequency is too high. When the car is moving away from the person, the person can hear the sound. If the speed of sound is 343 m/s, what is the minimum speed of the moving car?
Physics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

359 m/s

Explanation:

Highest frequency a person can hear is 20,000Hz.

f = c × λ

Frequency = Wave speed × Wavelength

Wavelength = 20,000 ÷ 343 = 58.31m

Wavespeed = Frequency ÷ Wavelength

c = 20,950 ÷ 58.31 = 359.3 m/s

= 359 m/s (3 s.f.)

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A metal block has a density of 5000 kg per cubic meter and a mass of 15,000 kg. What is its volume?
Naily [24]

Taking into account the definition of density, the volume of the metal block is 3 m³.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Volume of the metal block</h3>

In this case, you know that:

  • Density= 5000 \frac{kg}{m^{3} }
  • Mass= 15000 kg
  • Volume= ?

Replacing in the definition of density:

5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}

Solving:

volume×5000 \frac{kg}{m^{3} }= 15000 kg

volume= \frac{15000 kg}{5000 \frac{kg}{m^{3} }}

<u><em>volume= 3 m³</em></u>

In summary, the volume of the metal block is 3 m³.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ12

4 0
2 years ago
200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?
ArbitrLikvidat [17]

Answer:

 20N

Explanation:

Given parameters:

Work done  = 200J

Distance moved  = 10m

Unknown:

Amount of force applied  =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

      Work done  = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

           Force  = \frac{Work done}{distance}

           Force  = \frac{200}{10}   =  20N

5 0
4 years ago
The total pressure inside a 1.43 L cylinder at 28C is 1.03 atm. If the temperatures drops to -35C, and the volume remains the sa
Art [367]

Answer:

0.81452 atm

Explanation:

P_1 = Initial pressure = 1.43 L

V_1=V_2 = Volume

T_1 = Initial temperature = (28+273.15)  K

T_2 = Final temperature = (-35+273.15) K

P_2 = Final pressure

From the ideal gas law we have

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1V_1T_2}{T_2V_2}\\\Rightarrow P_2=\dfrac{1.03\times 1.43\times (273.15-35)}{(273.15+28)1.43}\\\Rightarrow P_2=0.81452\ atm

The pressure in the cylinder is 0.81452 atm

8 0
3 years ago
Please help. I'll mark you brainliest. ((:
alexgriva [62]
I believe that if you shine a light in the front of a binocular, then the light would condense and be more pin-pointed while if you point it through the part where your eyes go the light would blow up. Either way, the light will be refracted once it travels through the lenses. 
5 0
4 years ago
12 g … _____________________kilograms
Julli [10]
.012 kilograms Explanation.
3 0
4 years ago
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