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Mkey [24]
3 years ago
8

A loudspeaker in a parked car is producing sound whose frequency is 20950 Hz. A healthy young person with normal hearing is stan

ding nearby on the sidewalk but cannot hear the sound because the frequency is too high. When the car is moving away from the person, the person can hear the sound. If the speed of sound is 343 m/s, what is the minimum speed of the moving car?
Physics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

359 m/s

Explanation:

Highest frequency a person can hear is 20,000Hz.

f = c × λ

Frequency = Wave speed × Wavelength

Wavelength = 20,000 ÷ 343 = 58.31m

Wavespeed = Frequency ÷ Wavelength

c = 20,950 ÷ 58.31 = 359.3 m/s

= 359 m/s (3 s.f.)

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3 years ago
Consider a golf ball with a mass of 45.9 grams traveling at 200 km/hr. If an experiment is designed to measure the position of t
Kipish [7]

Answer:

speed of golf ball is 1.15 × 10^{-30} m/s

and % of uncertainty in speed =  2.07 × 10^{-30} %

Explanation:

given data

mass = 45.9 gram = 0.0459 kg

speed = 200 km/hr = 55.5 m/s

uncertainty position Δx = 1 mm = 10^{-3} m

to find out

speed of the golf ball and  % of speed of the golf ball

solution

we will apply here heisenberg uncertainty principle that is

uncertainty position ×uncertainty momentum ≥ \frac{h}{4\pi }    ......1

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here uncertainty momentum ΔPx = mΔVx

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so put here all these value in equation 1

10^{-3} × 0.0459 × ΔVx =  \frac{6.626*10^{-34}}{4\pi }

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and

so % of uncertainty in speed = ΔV / m

% of uncertainty in speed =  1.15 × 10^{-30}  / 55.5

% of uncertainty in speed =  2.07 × 10^{-30} %

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