The volume of a sample of ammonia gas : 5.152 L
<h3>Further explanation</h3>
Given
0.23 moles of ammonia
Required
The volume of a sample
Solution
Assumed on STP
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So for 0.23 moles :
= 0.23 x 22.4 L
= 5.152 L
Answer:
I saw B, he vented SUS
Explanation:
Iodoethane Is the answer.
Nitrate 2 , Hydrogen Oxygen , and Carbon Oxide
Answer:
the volume = 9.99 ml
Explanation:
in your Q we need to calculate the volume does the pipet deliver so , we are going to use this formula:
the volume = mass / density
here we need to know the density of water at a certain temperature 19 degrees Celsius ,so I used an external source to get the density of water at 19 degrees Celsius because it is changing with different temperatures
where mass here = 9.98 g
and the density of water at temperature 19 degrees Celsius= 0.998405mL
-1
by substitution :
the volume = 9.98 g / 0.998405mL
-1
≅ 9.996 ml = 10 ml
