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kotykmax [81]
3 years ago
11

What is the amount of energy for a photon that has a 125 cm wavelength

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer:

1.59 x 10⁻²⁵ J.

Explanation:

  • The energy of a photon is calculated Planck - Einstein's equation:

E = h ν , where

E is the energy of the photon,

h is  Planck's constant <em>(h = 6.626  x 10 ⁻³⁴ J.s)</em>

ν  is the frequency of the photon

  • There is a relation between the frequency (ν ) and wave length (λ).

λ.ν = c,

where c is the speed of light in vacuum (c = 3 .0 x 10 ⁸ m/s).

λ = 125 cm = 1.25 m.

<em>Now, E = h.c/λ.</em>

∴ E = h.c/λ = (6.626  x 10 ⁻³⁴ J.s) (3 .0 x 10 ⁸ m/s) / (1.25 m) = 1.59 x 10⁻²⁵ J.

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A central atom that is sp3 hybridized could bind up to how many other atoms?
inna [77]

Answer: up to 4 other atoms.

Explanation:

  • <em>Hybridization sp</em>³ means that the atom has 4 equal orbitals formed by the combination of 1 s and 3 p orbitals.

  • Each of these sp³ orbitals is a place for a chemical bonding.

  • Hence, since each orbital is able to bind a different atom, you conclude that <em>a central atom that is sp³ hydridized could bind up to 4 other atoms.</em>

This is precisely the case for carbon (C) atoms.

Carbon has atomic number 6. So its electron configuration is 1s² 2s²p².

The four electrons in the level 2, those shown in 2s² 2p², are in two different orbitals: two are in the orbital 2s and two are in the orbitals 2p.

This diagram shows how those 4 electrons fill the orbitals

  • 2s⇅ 2px↑ 2py↑

The two 2s electrons have lower energy level than the 2px and 2 py electrons, but the difference is not too big.That is why one of the electrons in the 2s ortital can be promoted to the empty 2pz orbital, and you get 4 equal hydridized ortibals, so called sp³.

And that is why, carbon (C) ends up with 4 equal (hydridized) orbitals which can bind up to 4 different atoms, including other carbon atoms, and so, form long chains and, virtually, infinite compounds.

5 0
4 years ago
What happens when sodium and sulfur combine
german

Answer:

It emits hydrogen sulfide...smells like rotten eggs..

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6 0
3 years ago
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Os supports combustion a chemical or physical property
Olegator [25]
Anything which changes the composition of starting material is a chemical property or chemical change. For example: you bake cake or cook food the heat changes composition of these. So cooking is a chemical change.

But evaporation of water is a physical change because even after evaporating it is still water molecules not changed to something else.

Combustion of any substance is burning of any substance in air. Combustion is actually the burning of a substance with oxygen in air. So, when a substance undergoes combustion it changes in it’s composition.

COMBUSTION IS A CHEMICAL CHANGE

7 0
3 years ago
Rate is related to?<br> A. Volume<br> B. Time<br> C. Distance <br> D. Percentage
Inga [223]
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6 0
4 years ago
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What is the maximum mass of glucose (C6H12O6) that can be burned in 10 g of oxygen?
Dahasolnce [82]
C_6H_{12}O_6 + 6 \ O_2 \to 6 \ CO_2 + 6 \ H_2O
1 mole of glucose : 6 moles of oxygen

First calculate the number of moles of oxygen in 10 g:
M=32 \ \frac{g}{mol} \\&#10;m=10 \ g \\&#10;n=\frac{10 \ g}{32 \ \frac{g}{mol}}=0.3125 \ mol

1 mole of glucose reacts with 6 moles of oxygen
x moles of glucose reacts with 0.3125 moles of oxygen
x=\frac{1 \ mol \cdot 0.3125 \ mol}{6 \ mol} = \frac{3125}{60000} \ mol= \frac{5}{96} \ mol

Now calculate the mass of 5/96 moles of glucose.
M=180 \ \frac{g}{mol} \\&#10;n=\frac{5}{96} \ mol \\&#10;m=180 \ \frac{g}{mol} \cdot \frac{5}{96} \ mol=\frac{900}{96} \ g=9.375 \ g

The maximum mass of glucose that can be burned in 10 g of oxygen is 9.375 g.
5 0
3 years ago
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