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Answer : We can produce 125.7 g of .
Explanation : The reaction will be
The molecular mass of is 64.1 g/mol
and molecular mass of is 34.1 g/mol
For every mole of we would need twice of
moles, so for every 3 moles of
we need 16 moles of
Now, we can calculate number of moles
2.61 X (3/16) = 0.49 moles
Here, the molecular mass of is 256.8 g
multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of .
Hence, 125.7 g of will be produced.