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Zolol [24]
1 year ago
12

The diagram shows one period of the Periodic Table. Li ,Be ,B , C,N,O,F,Ne .Which two elements form acidic oxides?

Chemistry
1 answer:
Rudik [331]1 year ago
6 0

Answer:

A -carbon and lithium.

Explanation:

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Given K = 3.61 at 45°C for the reaction A(g) + B(g) equilibrium reaction arrow C(g) and K = 7.19 at 45°C for the reaction 2 A(g)
Firlakuza [10]

Answer:

K = 0.55

Kp = 0.55

mol fraction B = 0.27

Explanation:

We need to calculate the equilibrium constant for the reaction:

C(g) + D(g) ⇄ 2B(g)              K₁= ?                       (1)

and we are given the following equilibria with their respective Ks

A(g) + B(g) ⇄ C(g)                 K₂= 3.61                 (2)

2 A(g) + D(g)  ⇄ C(g)             K₃= 7.19                 (3)

all at 45 ºC.

What we need to do to solve this question is to manipulate equations (2) and (3)  algebraically  to get our desired equilibrium (1).

We are allowed to reverse  reactions, in that case we take the reciprocal of K as our new K' ; we can also  add two equilibria together, and the new equilibrium constant will be the product of their respective Ks .

Finally if we multiply by a number then we raise the old constant to that factor to get the new equilibrium constant.

With all this  in mind, lets try to solve our question.

Notice A is not in our goal equilibrium (3)  and we want D as a reactant . That  suggests we should reverse the first equilibria and multiply it by two since we have 2 moles of B  as product in our  equilibrium (1) . Finally we would add (2) and (3) to get  (1) which is our final  goal.

2C(g)             ⇄  2A(g) + 2B(g)  K₂´= ( 1/ 3.61 )²  

                                   ₊

2 A(g) + D(g)  ⇄     C(g)               K₃ = 7.19  

<u>                                                                                    </u>

C(g) + D(g)     ⇄    2B(g)       K₁ = ( 1/ 3.61 )²   x  7.19

                                             K₁ = 0.55

Kp is the same as K = 0.55 since the equilibrium constant expression only involves  gases.

To compute the last part lets setup the following mnemonic  ICE table to determine the quantities at equilibrium:

pressure (atm)        C             D           B

initial                     1.64          1.64         0

change                    -x             -x        +2x

equilibrium          1.64-x         1.64-       2x

Thus since

Kp =0.55 = pB²/ (pC x pD) = (2x)²/ (1.64 -x)²  where p= partial pressure

Taking square root to both sides of the equation we have

√0.55 = 2x/(1.64 - x)

solving for x  we obtain a value of 0.44 atm.

Thus at equilibrium we have:

(1.64 - 0.44) atm = 1.20 atm = pC = p D

2(0.44) = 0.88 = pB

mole fraction of B = partial pressure of B divided into the total gas pressure:

X(B) = 0.88 / ( 1.20 + 1.20 + 0.88 ) = 0.27

8 0
3 years ago
For every action, there is an equal and opposite reaction.
Svetradugi [14.3K]

Answer:

yeah its newton's third law

Explanation:

7 0
2 years ago
How many total atoms in 3CuSO4
Step2247 [10]

Answer:

18

Explanation:

Element   Symbol   no of Atoms

Copper           Cu                3

Sulfur            S                3

Oxygen           O                  12

                                              18 = total

5 0
2 years ago
Read 2 more answers
Tare the balance. Put calorimeter (no lid) on the balance.
Paladinen [302]

Answer:12.46 g

Explanation:

3 0
3 years ago
What is the empirical formula for C8H20F4
AfilCa [17]

The given formula of C_{8} H_{2} O F_{4} can be written as C_{4} H_{10}-C_{4} H_{10}-F_{4}

<u>Explanation:</u>

Empirical formula is one of the way of representing the structural arrangement of any molecule. With this formula, we can guess the nearest atom or element in a heterogeneous molecules. Mostly the empirical and molecular formula differs for organic compounds.

As in organic compounds consists of chain of carbon and hydrogen elements. So while arranging them in a relation, we should remember that carbon should contain 4 nearby atoms and hydrogen can share only one electron to its nearby atom. Thus, a carbon can have three hydrogen and one carbon as neighbouring element.

So the given formula of C_{8} H_{2} O F_{4} can be written as

C_{4} H_{10}-C_{4} H_{10}-F_{4}

3 0
3 years ago
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