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ivolga24 [154]
3 years ago
9

Would it be C..? More NO2 and SO2 would form..help..please and thank you

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

C. More NO2 and SO2 will form

Explanation:

Le Chatelier's Principle : It  predicts the behavior of equilibrium due to change in pressure , temperature , volume , concentration etc

It states that When external changes are introduced in the equilibrium then it will shift the equilibrium in a direction to reduce the change.

In given Reaction SO3 is introduced(increased) .

So equilibrium will shift in the direction where SO3 should be consumed(decreased)

Hence the equilibrium will go in backward direction , i.e

NO + SO_{3} \rightarrow NO_{2} + SO_{2}

So more and more Of NO2 and SO2 will form

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3 years ago
If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
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<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

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3 years ago
an element "x" has the election configuration 2,8,3 this element is found in ______group and_____period A.3,llla B.llla,3 C.vlla
iogann1982 [59]

This element is found in group 3A, period 3

<h3>Further explanation </h3>

The maximum number of electrons that can be filled in the nth electron shell is 2n²(n=shell)

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  • L shell (n = 2) maximum 2 x 2² = 8 electrons
  • M shell (n = 3) maximum 2 x 3² = 18 electrons
  • N shell (n = 4) maximum 2 x 4² = 32 electrons

Electron configuration of element X : 2.8.3 , so :

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L shell = 8⇒2s²2p⁶

M shell = 3⇒ 3s²3p¹

Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids

The outer shell 3s²3p¹ : located in group 3A and period 3

group⇒valence electron ⇒3

period⇒the greatest value of the quantum number n⇒3

3 0
3 years ago
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