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pychu [463]
3 years ago
5

Gasoline has a density of 0.749 g/mL . There are 454 grams in a pound and 3.7854 L in a gallon. How many Pounds does 19.2 gallon

s of gasoline weigh?
Respond with correct number of significant figures in "E" notation.
Chemistry
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

119.9 pounds

Or 1.199e2 in E notation

Explanation:

First, find the total amount of liters.

3.7854 x 19.2 = 72.67968

There are 72.67968 liters of gasoline

Then, convert the liters to milliliters

72.67968 x 1000 = 72,679.68

There are 72,679.68 milliliters of gasoline

Now, convert it to grams

72,679.68 x 0.749 = 54,437.08032

There are 54,437.08032 grams of gasoline

Convert the grams to pounds

54,437.08032 ÷ 454 = 119.9054632599119

Round it with sig figs and you will find out the weight of the gasoline is 119.9 pounds.

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M&M balance equations
Alborosie

Answer:

Explanation:

To balance equations try to list out each element on both sides and start with the ones that aren't equal

6 0
3 years ago
For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.
FromTheMoon [43]

The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:

A. Hg₂SO₄

B. Na₂SO₄

C. Na⁺

D. NO₃⁻

E. SO₄⁻²

F. Hg₂(NO₃)₂

G. NaNO₃

H. Hg⁺²

Answer:

C, D, E, H

Explanation:

The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.

Thus, the reaction given:

Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃

So, let's do the dissociation.

Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;

Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;

HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;

NaNO₃ is formed by the ions Na⁺ and NO₃⁻.

Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.

7 0
3 years ago
Fun fact! <3
victus00 [196]

Answer:

:O Fr? Bet let me go get them lol

3 0
3 years ago
Read 2 more answers
In which of the titrations described below will the first (or only) equivalence point be reached upon the addition of 25.0 mL of
Mnenie [13.5K]

Answer:

1, 3, and 4

Step-by-step explanation:

We must calculate the volume of NaOH needed for each titration.

<em>1) HCl </em>

HCl + NaOH ⟶ NaCl + H₂O

n(HCl)       = 25.0 mL × (0.100 mmol/1mL) = 2.50 mmol

n(NaOH)  = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

<em>2) H₂C₂O₄ </em>

H₂C₂O₄ + NaOH ⟶ NaHC₂O₄

n(H₂C₂O₄) = 50.0 mL × (0.100 mmol/1mL) = 5.00 mmol

n(NaOH)    = 5.00 mmol H₂C₂O₄ × (1 mmol NaOH/1 mmol H₂C₂O₄)

= 5.00 mmol NaOH

V(NaOH)   = 5.00 mmol × (1 mL/0.100 mmol) = 50.0 mL

<em>3) HC₂H₃O₂ </em>

HC₂H₃O₂ + NaOH ⟶ NaC₂H₃O₂ + H₂O

n(HC₂H₃O₂) = 25.0 mL × (0.100 mmol/1mL) = 2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl)

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

<em>4) HBr </em>

HBr + NaOH ⟶ NaBr + H₂O

n(HBr) = 25.0 mL × (0.100 mmol/1mL) =2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl)

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

Titrations 1, 3, and 4 reach the first or only equivalence point  at 25.0 mL NaOH.

8 0
3 years ago
Read 2 more answers
a compound has an empirical formula of CH2 what is the molecular formula if it's molar mass is 252.5 grams/mol
Goryan [66]

Empirical formula is the simplest ratio of components making up the compound. the molecular formula is the actual ratio of components making up the compound.

the empirical formula is CH₂. We can find the mass of CH₂ one empirical unit and have to then find the number of empirical units in the molecular formula.

Mass of one empirical unit - CH₂ - 12 g/mol x 1 + 1 g/mol x 2 = 12 = 14 g

Molar mass of the compound is - 252 .5 g/mol

number of empirical units = molar mass / mass of empirical unit

                                           = \frac{252.5 g/mol}{14 g}

                                           = 18 units

Therefore molecular formula is - 18 times the empirical formula

molecular formula  - CH₂ x 18 = C₁₈H₃₆                                            

molecular formula is C₁₈H₃₆  

8 0
3 years ago
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