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pychu [463]
3 years ago
5

Gasoline has a density of 0.749 g/mL . There are 454 grams in a pound and 3.7854 L in a gallon. How many Pounds does 19.2 gallon

s of gasoline weigh?
Respond with correct number of significant figures in "E" notation.
Chemistry
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

119.9 pounds

Or 1.199e2 in E notation

Explanation:

First, find the total amount of liters.

3.7854 x 19.2 = 72.67968

There are 72.67968 liters of gasoline

Then, convert the liters to milliliters

72.67968 x 1000 = 72,679.68

There are 72,679.68 milliliters of gasoline

Now, convert it to grams

72,679.68 x 0.749 = 54,437.08032

There are 54,437.08032 grams of gasoline

Convert the grams to pounds

54,437.08032 ÷ 454 = 119.9054632599119

Round it with sig figs and you will find out the weight of the gasoline is 119.9 pounds.

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In a neutral atom, the number of protons is always equal to what other part of the atom?
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Answer:

b. The number of electrons

Explanation:

A "neutral atom" has a <u>neutral charge</u>. This means that <em>its charge is equal to </em><em>zero. </em>In order for the charges to cancel out each other, the atom's <em>positive charge should be equal to the negative charge. </em>These being said, the number of electrons<em> (negatively-charged)</em> is then equal to the number of protons <em>(positively-charged). </em>Those atoms which are not neutral are called <em>"ions."</em> This means that they either have more or less electrons than the protons.

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2 years ago
How much heat is absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon in the reaction SiO2(g) + 3C(s) → Si
defon

Answer:

31.24 kJ

Explanation:

  • SiO₂(g) + 3C(s) → SiC(s) + 2CO(g)        ΔH° = 624.7 kJ/mol

First we <u>convert 3.00 grams of SiO₂ to moles</u>, using its <em>molar mass</em>:

  • 3.00 g SiO₂ ÷ 60.08 g/mol = 0.05 mol

Now we <u>calculate the heat absorbed</u>, using the <em>given ΔH°</em>:

If the complete reaction of 1 mol of SiO₂ absorbs 624.7 kJ, then with 0.05 mol:

  • 0.05 mol * 624.7 kJ/mol = 31.24 kJ of heat would be absorbed.
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