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Mariana [72]
3 years ago
5

Helppppppppppp please

Chemistry
1 answer:
valentinak56 [21]3 years ago
4 0
Your answer would have to be #3
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An aqueous solution contains 0.100 m naoh at 25.0 °c. the ph of the solution is ________.
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Recall; pH + pOH = 14
In this case [OH-] =0.100 m
therefore;
pOH = -LOG[OH-]
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And since, pH +pOH = 14
Then pH = 14-pOH
                = 14 -1
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