Answer:
It has to have a problem base and a realistic explanation.
Explanation:
It needs to have enough information for you to be able to come up with an answer and realistic explanation.
Hope I helped :)
Answer: Mass of gas is 0.001 pounds.
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of gas = ?
Density of gas = 
Volume of gas = 389 ml = 0.389 L (1L=1000ml)
Putting in the values we get:
(1g =0.002 lb)
Thus the mass of gas is 0.001 pounds.
The mass of 2,301 grams of sodium in ounces is 0.0811757609 ounces.
The amount of sodium recommended by American heart association is 2301 mg. This limit should not be crossed in a day.
We have to convert Mass of sodium from mg to ounces.
We know,
1 ounce = 28.3459 grams.
We also know,
1 gram = 1000 milligrams.
So,
28.3459 grams = 28.3459 x 1000 milligrams.
28.3459 grams = 28345.9 milligrams.
1 ounce = 28345.9 mg.
1 mg = 1/28345.9 ounces
Weight of sodium 2301mg in ounces,
2301mg = 2301/28345.9 ounces
Dividing till last significant figure,
2301 mg = 0.0811757609 ounces.
Mass of sodium in ounces is 0.0811757609.
To know more about Unit conversion, visit,
brainly.com/question/97386
#SPJ9
Answer:
The molarity of a solution is 2.5 M
Explanation:
Molarity is a concentration unit that describes how much of a solution is dissolved in solution.
Molarity of a solution can found by using the formula,
Molarity (M) = (moles of solute)/(Liters of Solution).
Given, mass of Sodium = 114.95 grams.
Volume of water = 2 L.
Here, Sodium is solute as it is dissolved in water, which is the solvent.
Moles of Sodium(solute) can be found by using the formula,
Number of Moles = mass/Molecular weight.
mass of Sodium = 114.95 grams.
Molecular weight = 22.989 grams
Number of Moles of Sodium(solute) =114.95/22.989 = 5.
Substituting the values in the formula, we get,
M = 5/2 = 2.5 M
Answer: Option (d) is the correct answer.
Explanation:
An atom or element which has the ability to readily gain an electron will have high electronegativity.
Both Beryllium and Calcium are alkaline earth metals and hence they are electropositive in nature.
Whereas both iodine and nitrogen are electronegative in nature. But across the period there is an increase in electronegativity and down the group there is a decrease in electronegativity.
Nitrogen belongs to period 2 and iodine belongs to the bottom of group 17. Thus, we can conclude that nitrogen is more electronegative than iodine.
