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3 years ago

A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm?

Chemistry

2 answers:

Natalija [7]3 years ago

8 0

I believe it becomes less dense, bc when you heat something it’s molecules spread further apart.

Irina-Kira [14]3 years ago

7 0

Yes it becomes less dense because when the water molecules are hot it tends to go around more faster but if it was cold it would stay still. Just like us humans would do.

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If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

$\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}$

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

$\text{Moles of NO}_{2} = \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

$\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}$

(b) Mass of NO reacted

$\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}$

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

5 0

3 years ago

Vertical columns in the periodic table indicate what information? . . . A.. periods. . . B.. liquids. . . C.. synthetic elements

kozerog [31]

The answer is D. groups and families

8 0

3 years ago

Read 2 more answers

Based on the law of conservation of mass, which of the following statements is correct? Matter is neither created nor destroyed.

Dmitrij [34]

The first statement (Matter is neither created nor destroyed) is correct.

The second statement would violate the law of conservation of mass (I will refer to this as LCM), as it would mean matter can "flow" into the universe, but not out, meaning the total matter will never be less than it was before.

The third statement violates LCM because it means matter is created during a reaction, which is not true.

The last statement violates LCM because it means matter is lost during a reaction, which is not true.

7 0

3 years ago

Click the game tab at the bottom of the simulation and select level 1. (there is no seesaw balance for this part of the activity

Simora [160]

The strategy for balancing the equations is by looking at the number of atoms on each side of the equation and adding coefficients to the molecules.

<h3>What is a balanced equation?</h3>

A balanced equation is an equation for a chemical reaction where the number of atoms for each element in the reaction and the total charge is the same for the reactants and the products,

A strategy that will help balance equations more quickly is balancing by inspection. Here, you look at how many atoms you have on each side of the equation and add coefficients to the molecules to balance out the number of atoms.

Learn more about atoms on:

brainly.com/question/6258301

#SPJ1

6 0

2 years ago

For each of the following numbers, determine the number of significant figures it contains, rewrite it without using scientific

soldier1979 [14.2K]

Answer:

Explanation:

a) .0003050 significant figure - 4

b) 432.00 significant figure-5

c) .0000008001 significant figure -4

d) 200608.0 significant figure -7

e) .00001503 significant figure-4

f) 60751.0 significant figure- 6.

zero after decimal are all significant . zero before decimal is significant only when it is preceded by a digit.All digits are significant.

7 0

3 years ago